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leetcode-problemset/leetcode-cn/originData/minimum-number-of-swaps-to-make-the-string-balanced.json
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"question": {
"questionId": "2095",
"questionFrontendId": "1963",
"categoryTitle": "Algorithms",
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"title": "Minimum Number of Swaps to Make the String Balanced",
"titleSlug": "minimum-number-of-swaps-to-make-the-string-balanced",
"content": "<p>You are given a <strong>0-indexed</strong> string <code>s</code> of <strong>even</strong> length <code>n</code>. The string consists of <strong>exactly</strong> <code>n / 2</code> opening brackets <code>&#39;[&#39;</code> and <code>n / 2</code> closing brackets <code>&#39;]&#39;</code>.</p>\n\n<p>A string is called <strong>balanced</strong> if and only if:</p>\n\n<ul>\n\t<li>It is the empty string, or</li>\n\t<li>It can be written as <code>AB</code>, where both <code>A</code> and <code>B</code> are <strong>balanced</strong> strings, or</li>\n\t<li>It can be written as <code>[C]</code>, where <code>C</code> is a <strong>balanced</strong> string.</li>\n</ul>\n\n<p>You may swap the brackets at <strong>any</strong> two indices <strong>any</strong> number of times.</p>\n\n<p>Return <em>the <strong>minimum</strong> number of swaps to make </em><code>s</code> <em><strong>balanced</strong></em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;][][&quot;\n<strong>Output:</strong> 1\n<strong>Explanation:</strong> You can make the string balanced by swapping index 0 with index 3.\nThe resulting string is &quot;[[]]&quot;.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;]]][[[&quot;\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> You can do the following to make the string balanced:\n- Swap index 0 with index 4. s = &quot;[]][][&quot;.\n- Swap index 1 with index 5. s = &quot;[[][]]&quot;.\nThe resulting string is &quot;[[][]]&quot;.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;[]&quot;\n<strong>Output:</strong> 0\n<strong>Explanation:</strong> The string is already balanced.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == s.length</code></li>\n\t<li><code>2 &lt;= n &lt;= 10<sup>6</sup></code></li>\n\t<li><code>n</code> is even.</li>\n\t<li><code>s[i]</code> is either <code>&#39;[&#39; </code>or <code>&#39;]&#39;</code>.</li>\n\t<li>The number of opening brackets <code>&#39;[&#39;</code> equals <code>n / 2</code>, and the number of closing brackets <code>&#39;]&#39;</code> equals <code>n / 2</code>.</li>\n</ul>\n",
"translatedTitle": "使字符串平衡的最小交换次数",
"translatedContent": "<p>给你一个字符串 <code>s</code> <strong>下标从 0 开始</strong> ,且长度为偶数 <code>n</code> 。字符串 <strong>恰好</strong> 由 <code>n / 2</code> 个开括号 <code>'['</code> 和 <code>n / 2</code> 个闭括号 <code>']'</code> 组成。</p>\n\n<p>只有能满足下述所有条件的字符串才能称为 <strong>平衡字符串</strong> </p>\n\n<ul>\n\t<li>字符串是一个空字符串,或者</li>\n\t<li>字符串可以记作 <code>AB</code> ,其中 <code>A</code> 和 <code>B</code> 都是 <strong>平衡字符串</strong> ,或者</li>\n\t<li>字符串可以写成 <code>[C]</code> ,其中 <code>C</code> 是一个 <strong>平衡字符串</strong> 。</li>\n</ul>\n\n<p>你可以交换 <strong>任意</strong> 两个下标所对应的括号 <strong>任意</strong> 次数。</p>\n\n<p>返回使<em> </em><code>s</code> 变成 <strong>平衡字符串</strong> 所需要的 <strong>最小</strong> 交换次数。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<pre>\n<strong>输入:</strong>s = \"][][\"\n<strong>输出:</strong>1\n<strong>解释:</strong>交换下标 0 和下标 3 对应的括号,可以使字符串变成平衡字符串。\n最终字符串变成 \"[[]]\" 。\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>s = \"]]][[[\"\n<strong>输出:</strong>2\n<strong>解释:</strong>执行下述操作可以使字符串变成平衡字符串:\n- 交换下标 0 和下标 4 对应的括号s = \"[]][][\" 。\n- 交换下标 1 和下标 5 对应的括号s = \"[[][]]\" 。\n最终字符串变成 \"[[][]]\" 。\n</pre>\n\n<p><strong>示例 3</strong></p>\n\n<pre>\n<strong>输入:</strong>s = \"[]\"\n<strong>输出:</strong>0\n<strong>解释:</strong>这个字符串已经是平衡字符串。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>n == s.length</code></li>\n\t<li><code>2 &lt;= n &lt;= 10<sup>6</sup></code></li>\n\t<li><code>n</code> 为偶数</li>\n\t<li><code>s[i]</code> 为<code>'['</code> 或 <code>']'</code></li>\n\t<li>开括号 <code>'['</code> 的数目为 <code>n / 2</code> ,闭括号 <code>']'</code> 的数目也是 <code>n / 2</code></li>\n</ul>\n",
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"Iterate over the string and keep track of the number of opening and closing brackets on each step.",
"If the number of closing brackets is ever larger, you need to make a swap.",
"Swap it with the opening bracket closest to the end of s."
],
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