mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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177 lines
26 KiB
JSON
177 lines
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"title": "Minimum Absolute Difference Queries",
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"content": "<p>The <strong>minimum absolute difference</strong> of an array <code>a</code> is defined as the <strong>minimum value</strong> of <code>|a[i] - a[j]|</code>, where <code>0 <= i < j < a.length</code> and <code>a[i] != a[j]</code>. If all elements of <code>a</code> are the <strong>same</strong>, the minimum absolute difference is <code>-1</code>.</p>\n\n<ul>\n\t<li>For example, the minimum absolute difference of the array <code>[5,<u>2</u>,<u>3</u>,7,2]</code> is <code>|2 - 3| = 1</code>. Note that it is not <code>0</code> because <code>a[i]</code> and <code>a[j]</code> must be different.</li>\n</ul>\n\n<p>You are given an integer array <code>nums</code> and the array <code>queries</code> where <code>queries[i] = [l<sub>i</sub>, r<sub>i</sub>]</code>. For each query <code>i</code>, compute the <strong>minimum absolute difference</strong> of the <strong>subarray</strong> <code>nums[l<sub>i</sub>...r<sub>i</sub>]</code> containing the elements of <code>nums</code> between the <strong>0-based</strong> indices <code>l<sub>i</sub></code> and <code>r<sub>i</sub></code> (<strong>inclusive</strong>).</p>\n\n<p>Return <em>an <strong>array</strong> </em><code>ans</code> <em>where</em> <code>ans[i]</code> <em>is the answer to the</em> <code>i<sup>th</sup></code> <em>query</em>.</p>\n\n<p>A <strong>subarray</strong> is a contiguous sequence of elements in an array.</p>\n\n<p>The value of <code>|x|</code> is defined as:</p>\n\n<ul>\n\t<li><code>x</code> if <code>x >= 0</code>.</li>\n\t<li><code>-x</code> if <code>x < 0</code>.</li>\n</ul>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,3,4,8], queries = [[0,1],[1,2],[2,3],[0,3]]\n<strong>Output:</strong> [2,1,4,1]\n<strong>Explanation:</strong> The queries are processed as follows:\n- queries[0] = [0,1]: The subarray is [<u>1</u>,<u>3</u>] and the minimum absolute difference is |1-3| = 2.\n- queries[1] = [1,2]: The subarray is [<u>3</u>,<u>4</u>] and the minimum absolute difference is |3-4| = 1.\n- queries[2] = [2,3]: The subarray is [<u>4</u>,<u>8</u>] and the minimum absolute difference is |4-8| = 4.\n- queries[3] = [0,3]: The subarray is [1,<u>3</u>,<u>4</u>,8] and the minimum absolute difference is |3-4| = 1.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [4,5,2,2,7,10], queries = [[2,3],[0,2],[0,5],[3,5]]\n<strong>Output:</strong> [-1,1,1,3]\n<strong>Explanation: </strong>The queries are processed as follows:\n- queries[0] = [2,3]: The subarray is [2,2] and the minimum absolute difference is -1 because all the\n elements are the same.\n- queries[1] = [0,2]: The subarray is [<u>4</u>,<u>5</u>,2] and the minimum absolute difference is |4-5| = 1.\n- queries[2] = [0,5]: The subarray is [<u>4</u>,<u>5</u>,2,2,7,10] and the minimum absolute difference is |4-5| = 1.\n- queries[3] = [3,5]: The subarray is [2,<u>7</u>,<u>10</u>] and the minimum absolute difference is |7-10| = 3.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>2 <= nums.length <= 10<sup>5</sup></code></li>\n\t<li><code>1 <= nums[i] <= 100</code></li>\n\t<li><code>1 <= queries.length <= 2 * 10<sup>4</sup></code></li>\n\t<li><code>0 <= l<sub>i</sub> < r<sub>i</sub> < nums.length</code></li>\n</ul>\n",
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"translatedTitle": "查询差绝对值的最小值",
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"translatedContent": "<p>一个数组 <code>a</code> 的 <strong>差绝对值的最小值</strong> 定义为：<code>0 <= i < j < a.length</code> 且 <code>a[i] != a[j]</code> 的<strong> </strong><code><span style=\"\">|a[i] - a[j]|</span></code> 的 <strong>最小值</strong>。如果 <code>a</code> 中所有元素都 <strong>相同</strong> ，那么差绝对值的最小值为 <code>-1</code> 。</p>\n\n<ul>\n\t<li>比方说，数组 <code>[5,<strong>2</strong>,<strong>3</strong>,7,2]</code> 差绝对值的最小值是 <code>|2 - 3| = 1</code> 。注意答案不为 <code>0</code> ，因为 <code>a[i]</code> 和 <code>a[j]</code> 必须不相等。</li>\n</ul>\n\n<p>给你一个整数数组 <code>nums</code> 和查询数组 <code>queries</code> ，其中 <code>queries[i] = [l<sub>i</sub>, r<sub>i</sub>]</code> 。对于每个查询 <code>i</code> ，计算 <strong>子数组</strong> <code>nums[l<sub>i</sub>...r<sub>i</sub>]</code> 中 <strong>差绝对值的最小值</strong> ，子数组 <code>nums[l<sub>i</sub>...r<sub>i</sub>]</code> 包含 <code>nums</code> 数组（下标从 <strong>0</strong> 开始）中下标在 <code>l<sub>i</sub></code> 和 <code>r<sub>i</sub></code> 之间的所有元素（包含 <code>l<sub>i</sub></code> 和 <code>r<sub>i</sub></code> 在内）。</p>\n\n<p>请你返回 <code>ans</code> <strong>数组</strong>，其中 <code>ans[i]</code> 是第 <code>i</code> 个查询的答案。</p>\n\n<p><strong>子数组</strong> 是一个数组中连续的一段元素。</p>\n\n<p><code>|x|</code> 的值定义为：</p>\n\n<ul>\n\t<li>如果 <code>x >= 0</code> ，那么值为 <code>x</code> 。</li>\n\t<li>如果 <code>x < 0</code> ，那么值为 <code>-x</code> 。</li>\n</ul>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<b>输入：</b>nums = [1,3,4,8], queries = [[0,1],[1,2],[2,3],[0,3]]\n<b>输出：</b>[2,1,4,1]\n<b>解释：</b>查询结果如下：\n- queries[0] = [0,1]：子数组是 [<strong>1</strong>,<strong>3</strong>] ，差绝对值的最小值为 |1-3| = 2 。\n- queries[1] = [1,2]：子数组是 [<strong>3</strong>,<strong>4</strong>] ，差绝对值的最小值为 |3-4| = 1 。\n- queries[2] = [2,3]：子数组是 [<strong>4</strong>,<strong>8</strong>] ，差绝对值的最小值为 |4-8| = 4 。\n- queries[3] = [0,3]：子数组是 [1,<strong>3</strong>,<strong>4</strong>,8] ，差的绝对值的最小值为 |3-4| = 1 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<b>输入：</b>nums = [4,5,2,2,7,10], queries = [[2,3],[0,2],[0,5],[3,5]]\n<b>输出：</b>[-1,1,1,3]\n<strong>解释：</strong>查询结果如下：\n- queries[0] = [2,3]：子数组是 [2,2] ，差绝对值的最小值为 -1 ，因为所有元素相等。\n- queries[1] = [0,2]：子数组是 [<strong>4</strong>,<strong>5</strong>,2] ，差绝对值的最小值为 |4-5| = 1 。\n- queries[2] = [0,5]：子数组是 [<strong>4</strong>,<strong>5</strong>,2,2,7,10] ，差绝对值的最小值为 |4-5| = 1 。\n- queries[3] = [3,5]：子数组是 [2,<strong>7</strong>,<strong>10</strong>] ，差绝对值的最小值为 |7-10| = 3 。\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>2 <= nums.length <= 10<sup>5</sup></code></li>\n\t<li><code>1 <= nums[i] <= 100</code></li>\n\t<li><code>1 <= queries.length <= 2 * 10<sup>4</sup></code></li>\n\t<li><code>0 <= l<sub>i</sub> < r<sub>i</sub> < nums.length</code></li>\n</ul>\n",
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