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"categoryTitle": "Algorithms",
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"title": "Maximum Product of the Length of Two Palindromic Substrings",
"titleSlug": "maximum-product-of-the-length-of-two-palindromic-substrings",
"content": "<p>You are given a <strong>0-indexed</strong> string <code>s</code> and are tasked with finding two <strong>non-intersecting palindromic </strong>substrings of <strong>odd</strong> length such that the product of their lengths is maximized.</p>\n\n<p>More formally, you want to choose four integers <code>i</code>, <code>j</code>, <code>k</code>, <code>l</code> such that <code>0 &lt;= i &lt;= j &lt; k &lt;= l &lt; s.length</code> and both the substrings <code>s[i...j]</code> and <code>s[k...l]</code> are palindromes and have odd lengths. <code>s[i...j]</code> denotes a substring from index <code>i</code> to index <code>j</code> <strong>inclusive</strong>.</p>\n\n<p>Return <em>the <strong>maximum</strong> possible product of the lengths of the two non-intersecting palindromic substrings.</em></p>\n\n<p>A <strong>palindrome</strong> is a string that is the same forward and backward. A <strong>substring</strong> is a contiguous sequence of characters in a string.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;ababbb&quot;\n<strong>Output:</strong> 9\n<strong>Explanation:</strong> Substrings &quot;aba&quot; and &quot;bbb&quot; are palindromes with odd length. product = 3 * 3 = 9.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;zaaaxbbby&quot;\n<strong>Output:</strong> 9\n<strong>Explanation:</strong> Substrings &quot;aaa&quot; and &quot;bbb&quot; are palindromes with odd length. product = 3 * 3 = 9.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>2 &lt;= s.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>s</code> consists of lowercase English letters.</li>\n</ul>\n",
"translatedTitle": "两个回文子字符串长度的最大乘积",
"translatedContent": "<p>给你一个下标从 <strong>0</strong>&nbsp;开始的字符串&nbsp;<code>s</code>&nbsp;,你需要找到两个 <strong>不重叠</strong><strong>的回文&nbsp;</strong>子字符串,它们的长度都必须为 <strong>奇数</strong>&nbsp;,使得它们长度的乘积最大。</p>\n\n<p>更正式地,你想要选择四个整数&nbsp;<code>i</code>&nbsp;<code>j</code>&nbsp;<code>k</code>&nbsp;<code>l</code>&nbsp;,使得&nbsp;<code>0 &lt;= i &lt;= j &lt; k &lt;= l &lt; s.length</code>&nbsp;,且子字符串&nbsp;<code>s[i...j]</code> 和&nbsp;<code>s[k...l]</code>&nbsp;都是回文串且长度为奇数。<code>s[i...j]</code>&nbsp;表示下标从 <code>i</code>&nbsp;到 <code>j</code>&nbsp;且 <strong>包含</strong>&nbsp;两端下标的子字符串。</p>\n\n<p>请你返回两个不重叠回文子字符串长度的 <strong>最大</strong>&nbsp;乘积。</p>\n\n<p><strong>回文字符串</strong>&nbsp;指的是一个从前往后读和从后往前读一模一样的字符串。<strong>子字符串</strong>&nbsp;指的是一个字符串中一段连续字符。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<pre>\n<b>输入:</b>s = \"ababbb\"\n<b>输出:</b>9\n<b>解释:</b>子字符串 \"aba\" 和 \"bbb\" 为奇数长度的回文串。乘积为 3 * 3 = 9 。\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre>\n<b>输入:</b>s = \"zaaaxbbby\"\n<b>输出:</b>9\n<b>解释:</b>子字符串 \"aaa\" 和 \"bbb\" 为奇数长度的回文串。乘积为 3 * 3 = 9 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>2 &lt;= s.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>s</code>&nbsp;只包含小写英文字母。</li>\n</ul>\n",
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"You can use Manacher's algorithm to get the maximum palindromic substring centered at each index",
"After using Manacher's for each center use a line sweep from the center to the left and from the center to the right to find for each index the farthest center to it with distance ≤ palin[center]",
"After that, find the maximum palindrome size for each prefix in the string and for each suffix and the answer would be max(prefix[i] * suffix[i + 1])"
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