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"questionId": "2614",
"questionFrontendId": "2529",
"categoryTitle": "Algorithms",
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"title": "Maximum Count of Positive Integer and Negative Integer",
"titleSlug": "maximum-count-of-positive-integer-and-negative-integer",
"content": "<p>Given an array <code>nums</code> sorted in <strong>non-decreasing</strong> order, return <em>the maximum between the number of positive integers and the number of negative integers.</em></p>\n\n<ul>\n\t<li>In other words, if the number of positive integers in <code>nums</code> is <code>pos</code> and the number of negative integers is <code>neg</code>, then return the maximum of <code>pos</code> and <code>neg</code>.</li>\n</ul>\n\n<p><strong>Note</strong> that <code>0</code> is neither positive nor negative.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [-2,-1,-1,1,2,3]\n<strong>Output:</strong> 3\n<strong>Explanation:</strong> There are 3 positive integers and 3 negative integers. The maximum count among them is 3.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [-3,-2,-1,0,0,1,2]\n<strong>Output:</strong> 3\n<strong>Explanation:</strong> There are 2 positive integers and 3 negative integers. The maximum count among them is 3.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [5,20,66,1314]\n<strong>Output:</strong> 4\n<strong>Explanation:</strong> There are 4 positive integers and 0 negative integers. The maximum count among them is 4.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 2000</code></li>\n\t<li><code>-2000 &lt;= nums[i] &lt;= 2000</code></li>\n\t<li><code>nums</code> is sorted in a <strong>non-decreasing order</strong>.</li>\n</ul>\n\n<p>&nbsp;</p>\n<p><strong>Follow up:</strong> Can you solve the problem in <code>O(log(n))</code> time complexity?</p>\n",
"translatedTitle": "正整数和负整数的最大计数",
"translatedContent": "<p>给你一个按 <strong>非递减顺序</strong> 排列的数组 <code>nums</code> ,返回正整数数目和负整数数目中的最大值。</p>\n\n<ul>\n\t<li>换句话讲,如果 <code>nums</code> 中正整数的数目是 <code>pos</code> ,而负整数的数目是 <code>neg</code> ,返回 <code>pos</code> 和 <code>neg</code>二者中的最大值。</li>\n</ul>\n\n<p><strong>注意:</strong><code>0</code> 既不是正整数也不是负整数。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<pre>\n<strong>输入:</strong>nums = [-2,-1,-1,1,2,3]\n<strong>输出:</strong>3\n<strong>解释:</strong>共有 3 个正整数和 3 个负整数。计数得到的最大值是 3 。\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>nums = [-3,-2,-1,0,0,1,2]\n<strong>输出:</strong>3\n<strong>解释:</strong>共有 2 个正整数和 3 个负整数。计数得到的最大值是 3 。\n</pre>\n\n<p><strong>示例 3</strong></p>\n\n<pre>\n<strong>输入:</strong>nums = [5,20,66,1314]\n<strong>输出:</strong>4\n<strong>解释:</strong>共有 4 个正整数和 0 个负整数。计数得到的最大值是 4 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 2000</code></li>\n\t<li><code>-2000 &lt;= nums[i] &lt;= 2000</code></li>\n\t<li><code>nums</code> 按 <strong>非递减顺序</strong> 排列。</li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><strong>进阶:</strong>你可以设计并实现时间复杂度为 <code>O(log(n))</code> 的算法解决此问题吗?</p>\n",
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