leetcode-problemset/leetcode-cn/originData/longest-well-performing-interval.json

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            "categoryTitle": "Algorithms",
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            "title": "Longest Well-Performing Interval",
            "titleSlug": "longest-well-performing-interval",
            "content": "<p>We are given <code>hours</code>, a list of the number of hours worked per day for a given employee.</p>\n\n<p>A day is considered to be a <em>tiring day</em> if and only if the number of hours worked is (strictly) greater than <code>8</code>.</p>\n\n<p>A <em>well-performing interval</em> is an interval of days for which the number of tiring days is strictly larger than the number of non-tiring days.</p>\n\n<p>Return the length of the longest well-performing interval.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> hours = [9,9,6,0,6,6,9]\n<strong>Output:</strong> 3\n<strong>Explanation: </strong>The longest well-performing interval is [9,9,6].\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> hours = [6,6,6]\n<strong>Output:</strong> 0\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= hours.length &lt;= 10<sup>4</sup></code></li>\n\t<li><code>0 &lt;= hours[i] &lt;= 16</code></li>\n</ul>\n",
            "translatedTitle": "表现良好的最长时间段",
            "translatedContent": "<p>给你一份工作时间表&nbsp;<code>hours</code>，上面记录着某一位员工每天的工作小时数。</p>\n\n<p>我们认为当员工一天中的工作小时数大于&nbsp;<code>8</code> 小时的时候，那么这一天就是「<strong>劳累的一天</strong>」。</p>\n\n<p>所谓「表现良好的时间段」，意味在这段时间内，「劳累的天数」是严格<strong> 大于</strong>「不劳累的天数」。</p>\n\n<p>请你返回「表现良好时间段」的最大长度。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>hours = [9,9,6,0,6,6,9]\n<strong>输出：</strong>3\n<strong>解释：</strong>最长的表现良好时间段是 [9,9,6]。</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>hours = [6,6,6]\n<strong>输出：</strong>0\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= hours.length &lt;= 10<sup>4</sup></code></li>\n\t<li><code>0 &lt;= hours[i] &lt;= 16</code></li>\n</ul>\n",
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            "hints": [
                "Make a new array A of +1/-1s corresponding to if hours[i] is > 8 or not. The goal is to find the longest subarray with positive sum.",
                "Using prefix sums (PrefixSum[i+1] = A[0] + A[1] + ... + A[i]), you need to find for each j, the smallest i < j with PrefixSum[i] + 1 == PrefixSum[j]."
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