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leetcode-problemset/leetcode-cn/originData/longest-increasing-subsequence.json
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"categoryTitle": "Algorithms",
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"title": "Longest Increasing Subsequence",
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"content": "<p>Given an integer array <code>nums</code>, return <em>the length of the longest <strong>strictly increasing </strong></em><span data-keyword=\"subsequence-array\"><em><strong>subsequence</strong></em></span>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [10,9,2,5,3,7,101,18]\n<strong>Output:</strong> 4\n<strong>Explanation:</strong> The longest increasing subsequence is [2,3,7,101], therefore the length is 4.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [0,1,0,3,2,3]\n<strong>Output:</strong> 4\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [7,7,7,7,7,7,7]\n<strong>Output:</strong> 1\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 2500</code></li>\n\t<li><code>-10<sup>4</sup> &lt;= nums[i] &lt;= 10<sup>4</sup></code></li>\n</ul>\n\n<p>&nbsp;</p>\n<p><b>Follow up:</b>&nbsp;Can you come up with an algorithm that runs in&nbsp;<code>O(n log(n))</code> time complexity?</p>\n",
"translatedTitle": "最长递增子序列",
"translatedContent": "<p>给你一个整数数组 <code>nums</code> ,找到其中最长严格递增子序列的长度。</p>\n\n<p><strong>子序列&nbsp;</strong>是由数组派生而来的序列,删除(或不删除)数组中的元素而不改变其余元素的顺序。例如,<code>[3,6,2,7]</code> 是数组 <code>[0,3,1,6,2,2,7]</code> 的子序列。</p>\n&nbsp;\n\n<p><strong>示例 1</strong></p>\n\n<pre>\n<strong>输入:</strong>nums = [10,9,2,5,3,7,101,18]\n<strong>输出:</strong>4\n<strong>解释:</strong>最长递增子序列是 [2,3,7,101],因此长度为 4 。\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>nums = [0,1,0,3,2,3]\n<strong>输出:</strong>4\n</pre>\n\n<p><strong>示例 3</strong></p>\n\n<pre>\n<strong>输入:</strong>nums = [7,7,7,7,7,7,7]\n<strong>输出:</strong>1\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 2500</code></li>\n\t<li><code>-10<sup>4</sup> &lt;= nums[i] &lt;= 10<sup>4</sup></code></li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><b>进阶:</b></p>\n\n<ul>\n\t<li>你能将算法的时间复杂度降低到&nbsp;<code>O(n log(n))</code> 吗?</li>\n</ul>\n",
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