leetcode-problemset/leetcode-cn/originData/lexicographically-smallest-palindrome.json

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        "question": {
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            "title": "Lexicographically Smallest Palindrome",
            "titleSlug": "lexicographically-smallest-palindrome",
            "content": "<p>You are given a string <code node=\"[object Object]\">s</code> consisting of <strong>lowercase English letters</strong>, and you are allowed to perform operations on it. In one operation, you can <strong>replace</strong> a character in <code node=\"[object Object]\">s</code> with another lowercase English letter.</p>\n\n<p>Your task is to make <code node=\"[object Object]\">s</code> a <strong>palindrome</strong> with the <strong>minimum</strong> <strong>number</strong> <strong>of operations</strong> possible. If there are <strong>multiple palindromes</strong> that can be <meta charset=\"utf-8\" />made using the <strong>minimum</strong> number of operations, <meta charset=\"utf-8\" />make the <strong>lexicographically smallest</strong> one.</p>\n\n<p>A string <code>a</code> is lexicographically smaller than a string <code>b</code> (of the same length) if in the first position where <code>a</code> and <code>b</code> differ, string <code>a</code> has a letter that appears earlier in the alphabet than the corresponding letter in <code>b</code>.</p>\n\n<p>Return <em>the resulting palindrome string.</em></p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;egcfe&quot;\n<strong>Output:</strong> &quot;efcfe&quot;\n<strong>Explanation:</strong> The minimum number of operations to make &quot;egcfe&quot; a palindrome is 1, and the lexicographically smallest palindrome string we can get by modifying one character is &quot;efcfe&quot;, by changing &#39;g&#39;.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;abcd&quot;\n<strong>Output:</strong> &quot;abba&quot;\n<strong>Explanation:</strong> The minimum number of operations to make &quot;abcd&quot; a palindrome is 2, and the lexicographically smallest palindrome string we can get by modifying two characters is &quot;abba&quot;.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;seven&quot;\n<strong>Output:</strong> &quot;neven&quot;\n<strong>Explanation:</strong> The minimum number of operations to make &quot;seven&quot; a palindrome is 1, and the lexicographically smallest palindrome string we can get by modifying one character is &quot;neven&quot;.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 1000</code></li>\n\t<li><code>s</code>&nbsp;consists of only lowercase English letters<b>.</b></li>\n</ul>\n",
            "translatedTitle": "字典序最小回文串",
            "translatedContent": "<p>给你一个由 <strong>小写英文字母</strong> 组成的字符串 <code>s</code> ，你可以对其执行一些操作。在一步操作中，你可以用其他小写英文字母 <strong>替换</strong>&nbsp; <code>s</code> 中的一个字符。</p>\n\n<p>请你执行 <strong>尽可能少的操作</strong> ，使 <code>s</code> 变成一个 <strong>回文串</strong> 。如果执行 <strong>最少</strong> 操作次数的方案不止一种，则只需选取 <strong>字典序最小</strong> 的方案。</p>\n\n<p>对于两个长度相同的字符串 <code>a</code> 和 <code>b</code> ，在 <code>a</code> 和 <code>b</code> 出现不同的第一个位置，如果该位置上 <code>a</code> 中对应字母比 <code>b</code> 中对应字母在字母表中出现顺序更早，则认为 <code>a</code> 的字典序比 <code>b</code> 的字典序要小。</p>\n\n<p>返回最终的回文字符串。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>s = \"egcfe\"\n<strong>输出：</strong>\"efcfe\"\n<strong>解释：</strong>将 \"egcfe\" 变成回文字符串的最小操作次数为 1 ，修改 1 次得到的字典序最小回文字符串是 \"efcfe\"，只需将 'g' 改为 'f' 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>s = \"abcd\"\n<strong>输出：</strong>\"abba\"\n<strong>解释：</strong>将 \"abcd\" 变成回文字符串的最小操作次数为 2 ，修改 2 次得到的字典序最小回文字符串是 \"abba\" 。\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>s = \"seven\"\n<strong>输出：</strong>\"neven\"\n<strong>解释：</strong>将 \"seven\" 变成回文字符串的最小操作次数为 1 ，修改 1 次得到的字典序最小回文字符串是 \"neven\" 。</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 1000</code></li>\n\t<li><code>s</code> 仅由小写英文字母组成</li>\n</ul>\n",
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            "hints": [
                "We can make any string a palindrome, by simply making any character at index i equal to the character at index length - i - 1 (using 0-based indexing).",
                "To make it lexicographically smallest we can change the character with maximum ASCII value to the one with minimum ASCII value."
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