mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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183 lines
21 KiB
JSON
183 lines
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JSON
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"title": "Get Maximum in Generated Array",
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"content": "<p>You are given an integer <code>n</code>. A <strong>0-indexed</strong> integer array <code>nums</code> of length <code>n + 1</code> is generated in the following way:</p>\n\n<ul>\n\t<li><code>nums[0] = 0</code></li>\n\t<li><code>nums[1] = 1</code></li>\n\t<li><code>nums[2 * i] = nums[i]</code> when <code>2 <= 2 * i <= n</code></li>\n\t<li><code>nums[2 * i + 1] = nums[i] + nums[i + 1]</code> when <code>2 <= 2 * i + 1 <= n</code></li>\n</ul>\n\n<p>Return<strong> </strong><em>the <strong>maximum</strong> integer in the array </em><code>nums</code>.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 7\n<strong>Output:</strong> 3\n<strong>Explanation:</strong> According to the given rules:\n nums[0] = 0\n nums[1] = 1\n nums[(1 * 2) = 2] = nums[1] = 1\n nums[(1 * 2) + 1 = 3] = nums[1] + nums[2] = 1 + 1 = 2\n nums[(2 * 2) = 4] = nums[2] = 1\n nums[(2 * 2) + 1 = 5] = nums[2] + nums[3] = 1 + 2 = 3\n nums[(3 * 2) = 6] = nums[3] = 2\n nums[(3 * 2) + 1 = 7] = nums[3] + nums[4] = 2 + 1 = 3\nHence, nums = [0,1,1,2,1,3,2,3], and the maximum is max(0,1,1,2,1,3,2,3) = 3.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 2\n<strong>Output:</strong> 1\n<strong>Explanation:</strong> According to the given rules, nums = [0,1,1]. The maximum is max(0,1,1) = 1.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 3\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> According to the given rules, nums = [0,1,1,2]. The maximum is max(0,1,1,2) = 2.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>0 <= n <= 100</code></li>\n</ul>\n",
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"translatedTitle": "获取生成数组中的最大值",
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"translatedContent": "<p>给你一个整数 <code>n</code> 。按下述规则生成一个长度为 <code>n + 1</code> 的数组 <code>nums</code> ：</p>\n\n<ul>\n\t<li><code>nums[0] = 0</code></li>\n\t<li><code>nums[1] = 1</code></li>\n\t<li>当 <code>2 <= 2 * i <= n</code> 时，<code>nums[2 * i] = nums[i]</code></li>\n\t<li>当 <code>2 <= 2 * i + 1 <= n</code> 时，<code>nums[2 * i + 1] = nums[i] + nums[i + 1]</code></li>\n</ul>\n\n<p>返回生成数组 <code>nums</code> 中的 <strong>最大</strong> 值。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>n = 7\n<strong>输出：</strong>3\n<strong>解释：</strong>根据规则：\n nums[0] = 0\n nums[1] = 1\n nums[(1 * 2) = 2] = nums[1] = 1\n nums[(1 * 2) + 1 = 3] = nums[1] + nums[2] = 1 + 1 = 2\n nums[(2 * 2) = 4] = nums[2] = 1\n nums[(2 * 2) + 1 = 5] = nums[2] + nums[3] = 1 + 2 = 3\n nums[(3 * 2) = 6] = nums[3] = 2\n nums[(3 * 2) + 1 = 7] = nums[3] + nums[4] = 2 + 1 = 3\n因此，nums = [0,1,1,2,1,3,2,3]，最大值 3\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>n = 2\n<strong>输出：</strong>1\n<strong>解释：</strong>根据规则，nums[0]、nums[1] 和 nums[2] 之中的最大值是 1\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>n = 3\n<strong>输出：</strong>2\n<strong>解释：</strong>根据规则，nums[0]、nums[1]、nums[2] 和 nums[3] 之中的最大值是 2\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>0 <= n <= 100</code></li>\n</ul>\n",
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