mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-10 18:48:13 +08:00
183 lines
24 KiB
JSON
183 lines
24 KiB
JSON
{
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"questionId": "1513",
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"questionFrontendId": "1397",
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"categoryTitle": "Algorithms",
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"boundTopicId": 170712,
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"title": "Find All Good Strings",
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"content": "<p>Given the strings <code>s1</code> and <code>s2</code> of size <code>n</code> and the string <code>evil</code>, return <em>the number of <strong>good</strong> strings</em>.</p>\n\n<p>A <strong>good</strong> string has size <code>n</code>, it is alphabetically greater than or equal to <code>s1</code>, it is alphabetically smaller than or equal to <code>s2</code>, and it does not contain the string <code>evil</code> as a substring. Since the answer can be a huge number, return this <strong>modulo</strong> <code>10<sup>9</sup> + 7</code>.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 2, s1 = "aa", s2 = "da", evil = "b"\n<strong>Output:</strong> 51 \n<strong>Explanation:</strong> There are 25 good strings starting with 'a': "aa","ac","ad",...,"az". Then there are 25 good strings starting with 'c': "ca","cc","cd",...,"cz" and finally there is one good string starting with 'd': "da". \n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 8, s1 = "leetcode", s2 = "leetgoes", evil = "leet"\n<strong>Output:</strong> 0 \n<strong>Explanation:</strong> All strings greater than or equal to s1 and smaller than or equal to s2 start with the prefix "leet", therefore, there is not any good string.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 2, s1 = "gx", s2 = "gz", evil = "x"\n<strong>Output:</strong> 2\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>s1.length == n</code></li>\n\t<li><code>s2.length == n</code></li>\n\t<li><code>s1 <= s2</code></li>\n\t<li><code>1 <= n <= 500</code></li>\n\t<li><code>1 <= evil.length <= 50</code></li>\n\t<li>All strings consist of lowercase English letters.</li>\n</ul>\n",
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"translatedTitle": "找到所有好字符串",
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"translatedContent": "<p>给你两个长度为 <code>n</code> 的字符串 <code>s1</code> 和 <code>s2</code> ，以及一个字符串 <code>evil</code> 。请你返回 <strong>好字符串 </strong>的数目。</p>\n\n<p><strong>好字符串</strong> 的定义为：它的长度为 <code>n</code> ，字典序大于等于 <code>s1</code> ，字典序小于等于 <code>s2</code> ，且不包含 <code>evil</code> 为子字符串。</p>\n\n<p>由于答案可能很大，请你返回答案对 10^9 + 7 取余的结果。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><strong>输入：</strong>n = 2, s1 = "aa", s2 = "da", evil = "b"\n<strong>输出：</strong>51 \n<strong>解释：</strong>总共有 25 个以 'a' 开头的好字符串："aa"，"ac"，"ad"，...，"az"。还有 25 个以 'c' 开头的好字符串："ca"，"cc"，"cd"，...，"cz"。最后，还有一个以 'd' 开头的好字符串："da"。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><strong>输入：</strong>n = 8, s1 = "leetcode", s2 = "leetgoes", evil = "leet"\n<strong>输出：</strong>0 \n<strong>解释：</strong>所有字典序大于等于 s1 且小于等于 s2 的字符串都以 evil 字符串 "leet" 开头。所以没有好字符串。\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre><strong>输入：</strong>n = 2, s1 = "gx", s2 = "gz", evil = "x"\n<strong>输出：</strong>2\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>s1.length == n</code></li>\n\t<li><code>s2.length == n</code></li>\n\t<li><code>s1 <= s2</code></li>\n\t<li><code>1 <= n <= 500</code></li>\n\t<li><code>1 <= evil.length <= 50</code></li>\n\t<li>所有字符串都只包含小写英文字母。</li>\n</ul>\n",
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"Use DP with 4 states (pos: Int, posEvil: Int, equalToS1: Bool, equalToS2: Bool) which compute the number of valid strings of size \"pos\" where the maximum common suffix with string \"evil\" has size \"posEvil\". When \"equalToS1\" is \"true\", the current valid string is equal to \"S1\" otherwise it is greater. In a similar way when equalToS2 is \"true\" the current valid string is equal to \"S2\" otherwise it is smaller.",
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"To update the maximum common suffix with string \"evil\" use KMP preprocessing."
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href=\\\"https:\\/\\/github.com\\/emirpasic\\/gods\\/tree\\/v1.18.1\\\" target=\\\"_blank\\\">https:\\/\\/godoc.org\\/github.com\\/emirpasic\\/gods@v1.18.1<\\/a> \\u7b2c\\u4e09\\u65b9\\u5e93\\u3002<\\/p>\"],\"python3\":[\"Python3\",\"<p>\\u7248\\u672c\\uff1a<code>Python 3.10<\\/code><\\/p>\\r\\n\\r\\n<p>\\u4e3a\\u4e86\\u65b9\\u4fbf\\u8d77\\u89c1\\uff0c\\u5927\\u90e8\\u5206\\u5e38\\u7528\\u5e93\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8 \\u5bfc\\u5165\\uff0c\\u5982<a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/array.html\\\" target=\\\"_blank\\\">array<\\/a>, <a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/bisect.html\\\" target=\\\"_blank\\\">bisect<\\/a>, <a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/collections.html\\\" target=\\\"_blank\\\">collections<\\/a>\\u3002 \\u5982\\u679c\\u60a8\\u9700\\u8981\\u4f7f\\u7528\\u5176\\u4ed6\\u5e93\\u51fd\\u6570\\uff0c\\u8bf7\\u81ea\\u884c\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n<p>\\u5982\\u9700\\u4f7f\\u7528 Map\\/TreeMap 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