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leetcode-problemset/leetcode-cn/originData/count-all-valid-pickup-and-delivery-options.json
2023-12-09 19:57:46 +08:00

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"categoryTitle": "Algorithms",
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"title": "Count All Valid Pickup and Delivery Options",
"titleSlug": "count-all-valid-pickup-and-delivery-options",
"content": "<p>Given <code>n</code> orders, each order consists of a pickup and a delivery service.</p>\n\n<p>Count all valid pickup/delivery possible sequences such that delivery(i) is always after of&nbsp;pickup(i).&nbsp;</p>\n\n<p>Since the answer&nbsp;may be too large,&nbsp;return it modulo&nbsp;10^9 + 7.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 1\n<strong>Output:</strong> 1\n<strong>Explanation:</strong> Unique order (P1, D1), Delivery 1 always is after of Pickup 1.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 2\n<strong>Output:</strong> 6\n<strong>Explanation:</strong> All possible orders: \n(P1,P2,D1,D2), (P1,P2,D2,D1), (P1,D1,P2,D2), (P2,P1,D1,D2), (P2,P1,D2,D1) and (P2,D2,P1,D1).\nThis is an invalid order (P1,D2,P2,D1) because Pickup 2 is after of Delivery 2.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 3\n<strong>Output:</strong> 90\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n &lt;= 500</code></li>\n</ul>\n",
"translatedTitle": "有效的快递序列数目",
"translatedContent": "<p>给你&nbsp;<code>n</code>&nbsp;笔订单,每笔订单都需要快递服务。</p>\n\n<p>计算所有有效的 取货 / 交付 可能的顺序,使 delivery(i) 总是在 pickup(i) 之后。</p>\n\n<p>由于答案可能很大,请返回答案对 10^9 + 7 取余的结果。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<pre>\n<strong>输入:</strong>n = 1\n<strong>输出:</strong>1\n<strong>解释:</strong>只有一种序列 (P1, D1),物品 1 的配送服务D1在物品 1 的收件服务P1后。\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>n = 2\n<strong>输出:</strong>6\n<strong>解释:</strong>所有可能的序列包括:\n(P1,P2,D1,D2)(P1,P2,D2,D1)(P1,D1,P2,D2)(P2,P1,D1,D2)(P2,P1,D2,D1) 和 (P2,D2,P1,D1)。\n(P1,D2,P2,D1) 是一个无效的序列,因为物品 2 的收件服务P2不应在物品 2 的配送服务D2之后。\n</pre>\n\n<p><strong>示例 3</strong></p>\n\n<pre>\n<strong>输入:</strong>n = 3\n<strong>输出:</strong>90\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n &lt;= 500</code></li>\n</ul>\n",
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