leetcode-problemset/leetcode-cn/originData/construct-binary-tree-from-preorder-and-postorder-traversal.json

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        "question": {
            "questionId": "925",
            "questionFrontendId": "889",
            "categoryTitle": "Algorithms",
            "boundTopicId": 1681,
            "title": "Construct Binary Tree from Preorder and Postorder Traversal",
            "titleSlug": "construct-binary-tree-from-preorder-and-postorder-traversal",
            "content": "<p>Given two integer arrays, <code>preorder</code> and <code>postorder</code> where <code>preorder</code> is the preorder traversal of a binary tree of <strong>distinct</strong> values and <code>postorder</code> is the postorder traversal of the same tree, reconstruct and return <em>the binary tree</em>.</p>\n\n<p>If there exist multiple answers, you can <strong>return any</strong> of them.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/07/24/lc-prepost.jpg\" style=\"width: 304px; height: 265px;\" />\n<pre>\n<strong>Input:</strong> preorder = [1,2,4,5,3,6,7], postorder = [4,5,2,6,7,3,1]\n<strong>Output:</strong> [1,2,3,4,5,6,7]\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> preorder = [1], postorder = [1]\n<strong>Output:</strong> [1]\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= preorder.length &lt;= 30</code></li>\n\t<li><code>1 &lt;= preorder[i] &lt;= preorder.length</code></li>\n\t<li>All the values of <code>preorder</code> are <strong>unique</strong>.</li>\n\t<li><code>postorder.length == preorder.length</code></li>\n\t<li><code>1 &lt;= postorder[i] &lt;= postorder.length</code></li>\n\t<li>All the values of <code>postorder</code> are <strong>unique</strong>.</li>\n\t<li>It is guaranteed that <code>preorder</code> and <code>postorder</code> are the preorder traversal and postorder traversal of the same binary tree.</li>\n</ul>\n",
            "translatedTitle": "根据前序和后序遍历构造二叉树",
            "translatedContent": "<p>给定两个整数数组，<code>preorder</code>&nbsp;和 <code>postorder</code> ，其中 <code>preorder</code> 是一个具有 <strong>无重复</strong> 值的二叉树的前序遍历，<code>postorder</code> 是同一棵树的后序遍历，重构并返回二叉树。</p>\n\n<p>如果存在多个答案，您可以返回其中 <strong>任何</strong> 一个。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<p><img src=\"https://assets.leetcode.com/uploads/2021/07/24/lc-prepost.jpg\" style=\"height: 265px; width: 304px;\" /></p>\n\n<pre>\n<strong>输入：</strong>preorder = [1,2,4,5,3,6,7], postorder = [4,5,2,6,7,3,1]\n<strong>输出：</strong>[1,2,3,4,5,6,7]\n</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<pre>\n<strong>输入:</strong> preorder = [1], postorder = [1]\n<strong>输出:</strong> [1]\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= preorder.length &lt;= 30</code></li>\n\t<li><code>1 &lt;= preorder[i] &lt;= preorder.length</code></li>\n\t<li><code>preorder</code>&nbsp;中所有值都 <strong>不同</strong></li>\n\t<li><code>postorder.length == preorder.length</code></li>\n\t<li><code>1 &lt;= postorder[i] &lt;= postorder.length</code></li>\n\t<li><code>postorder</code>&nbsp;中所有值都 <strong>不同</strong></li>\n\t<li>保证 <code>preorder</code>&nbsp;和 <code>postorder</code>&nbsp;是同一棵二叉树的前序遍历和后序遍历</li>\n</ul>\n",
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                    "code": "/**\n * Definition for a binary tree node.\n * struct TreeNode {\n *     int val;\n *     TreeNode *left;\n *     TreeNode *right;\n *     TreeNode() : val(0), left(nullptr), right(nullptr) {}\n *     TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}\n *     TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}\n * };\n */\nclass Solution {\npublic:\n    TreeNode* constructFromPrePost(vector<int>& preorder, vector<int>& postorder) {\n\n    }\n};",
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                    "code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n *     int val;\n *     TreeNode left;\n *     TreeNode right;\n *     TreeNode() {}\n *     TreeNode(int val) { this.val = val; }\n *     TreeNode(int val, TreeNode left, TreeNode right) {\n *         this.val = val;\n *         this.left = left;\n *         this.right = right;\n *     }\n * }\n */\nclass Solution {\n    public TreeNode constructFromPrePost(int[] preorder, int[] postorder) {\n\n    }\n}",
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                    "code": "# Definition for a binary tree node.\n# class TreeNode:\n#     def __init__(self, val=0, left=None, right=None):\n#         self.val = val\n#         self.left = left\n#         self.right = right\nclass Solution:\n    def constructFromPrePost(self, preorder: List[int], postorder: List[int]) -> Optional[TreeNode]:",
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                    "code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n *     public int val;\n *     public TreeNode left;\n *     public TreeNode right;\n *     public TreeNode(int val=0, TreeNode left=null, TreeNode right=null) {\n *         this.val = val;\n *         this.left = left;\n *         this.right = right;\n *     }\n * }\n */\npublic class Solution {\n    public TreeNode ConstructFromPrePost(int[] preorder, int[] postorder) {\n\n    }\n}",
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                    "code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n *     val: number\n *     left: TreeNode | null\n *     right: TreeNode | null\n *     constructor(val?: number, left?: TreeNode | null, right?: TreeNode | null) {\n *         this.val = (val===undefined ? 0 : val)\n *         this.left = (left===undefined ? null : left)\n *         this.right = (right===undefined ? null : right)\n *     }\n * }\n */\n\nfunction constructFromPrePost(preorder: number[], postorder: number[]): TreeNode | null {\n    \n};",
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                    "code": "/**\n * Definition for a binary tree node.\n * type TreeNode struct {\n *     Val int\n *     Left *TreeNode\n *     Right *TreeNode\n * }\n */\nfunc constructFromPrePost(preorder []int, postorder []int) *TreeNode {\n\n}",
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