leetcode-problemset/leetcode-cn/originData/coin-bonus.json

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            "questionId": "100094",
            "questionFrontendId": "LCP 05",
            "categoryTitle": "Algorithms",
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            "title": "Coin Bonus",
            "titleSlug": "coin-bonus",
            "content": "<p>English description is not available for the problem. Please switch to Chinese.</p>\r\n",
            "translatedTitle": "发 LeetCoin",
            "translatedContent": "<p>力扣决定给一个刷题团队发<code>LeetCoin</code>作为奖励。同时，为了监控给大家发了多少<code>LeetCoin</code>，力扣有时候也会进行查询。</p>\n\n<p>&nbsp;</p>\n\n<p>该刷题团队的管理模式可以用一棵树表示：</p>\n\n<ol>\n\t<li>团队只有一个负责人，编号为1。除了该负责人外，每个人有且仅有一个领导（负责人没有领导）；</li>\n\t<li>不存在循环管理的情况，如A管理B，B管理C，C管理A。</li>\n</ol>\n\n<p>&nbsp;</p>\n\n<p>力扣想进行的操作有以下三种：</p>\n\n<ol>\n\t<li>给团队的一个成员（也可以是负责人）发一定数量的<code>LeetCoin</code>；</li>\n\t<li>给团队的一个成员（也可以是负责人），以及他/她管理的所有人（即他/她的下属、他/她下属的下属，&hellip;&hellip;），发一定数量的<code>LeetCoin</code>；</li>\n\t<li>查询某一个成员（也可以是负责人），以及他/她管理的所有人被发到的<code>LeetCoin</code>之和。</li>\n</ol>\n\n<p>&nbsp;</p>\n\n<p><strong>输入：</strong></p>\n\n<ol>\n\t<li><code>N</code>表示团队成员的个数（编号为1～N，负责人为1）；</li>\n\t<li><code>leadership</code>是大小为<code>(N&nbsp;- 1) * 2</code>的二维数组，其中每个元素<code>[a, b]</code>代表<code>b</code>是<code>a</code>的下属；</li>\n\t<li><code>operations</code>是一个长度为<code>Q</code>的二维数组，代表以时间排序的操作，格式如下：\n\t<ol>\n\t\t<li><code>operations[i][0] = 1</code>: 代表第一种操作，<code>operations[i][1]</code>代表成员的编号，<code>operations[i][2]</code>代表<code>LeetCoin</code>的数量；</li>\n\t\t<li><code>operations[i][0] = 2</code>: 代表第二种操作，<code>operations[i][1]</code>代表成员的编号，<code>operations[i][2]</code>代表<code>LeetCoin</code>的数量；</li>\n\t\t<li><code>operations[i][0] = 3</code>: 代表第三种操作，<code>operations[i][1]</code>代表成员的编号；</li>\n\t</ol>\n\t</li>\n</ol>\n\n<p><strong>输出：</strong></p>\n\n<p>返回一个数组，数组里是每次<strong>查询</strong>的返回值（发<code>LeetCoin</code>的操作不需要任何返回值）。由于发的<code>LeetCoin</code>很多，请把每次查询的结果模<code>1e9+7 (1000000007)</code>。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><strong>输入：</strong>N = 6, leadership = [[1, 2], [1, 6], [2, 3], [2, 5], [1, 4]], operations = [[1, 1, 500], [2, 2, 50], [3, 1], [2, 6, 15], [3, 1]]\n<strong>输出：</strong>[650, 665]\n<strong>解释：</strong>团队的管理关系见下图。\n第一次查询时，每个成员得到的LeetCoin的数量分别为（按编号顺序）：500, 50, 50, 0, 50, 0;\n第二次查询时，每个成员得到的LeetCoin的数量分别为（按编号顺序）：500, 50, 50, 0, 50, 15.\n</pre>\n\n<p><img alt=\"\" src=\"https://assets.leetcode-cn.com/aliyun-lc-upload/uploads/2019/09/09/coin_example_1.jpg\" style=\"height: 344px; width: 300px;\"></p>\n\n<p>&nbsp;</p>\n\n<p><strong>限制：</strong></p>\n\n<ol>\n\t<li><code>1 &lt;= N &lt;= 50000</code></li>\n\t<li><code>1 &lt;= Q &lt;= 50000</code></li>\n\t<li><code>operations[i][0] != 3 时，1 &lt;= operations[i][2]&nbsp;&lt;= 5000</code></li>\n</ol>\n",
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