mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-10 18:48:13 +08:00
171 lines
20 KiB
JSON
171 lines
20 KiB
JSON
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"questionId": "1276",
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"questionFrontendId": "1362",
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"categoryTitle": "Algorithms",
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"boundTopicId": 102339,
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"title": "Closest Divisors",
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"titleSlug": "closest-divisors",
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"content": "<p>Given an integer <code>num</code>, find the closest two integers in absolute difference whose product equals <code>num + 1</code> or <code>num + 2</code>.</p>\n\n<p>Return the two integers in any order.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> num = 8\n<strong>Output:</strong> [3,3]\n<strong>Explanation:</strong> For num + 1 = 9, the closest divisors are 3 & 3, for num + 2 = 10, the closest divisors are 2 & 5, hence 3 & 3 is chosen.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> num = 123\n<strong>Output:</strong> [5,25]\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> num = 999\n<strong>Output:</strong> [40,25]\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= num <= 10^9</code></li>\n</ul>\n",
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"translatedTitle": "最接近的因数",
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"translatedContent": "<p>给你一个整数 <code>num</code>，请你找出同时满足下面全部要求的两个整数：</p>\n\n<ul>\n\t<li>两数乘积等于 <code>num + 1</code> 或 <code>num + 2</code></li>\n\t<li>以绝对差进行度量，两数大小最接近</li>\n</ul>\n\n<p>你可以按任意顺序返回这两个整数。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><strong>输入：</strong>num = 8\n<strong>输出：</strong>[3,3]\n<strong>解释：</strong>对于 num + 1 = 9，最接近的两个因数是 3 & 3；对于 num + 2 = 10, 最接近的两个因数是 2 & 5，因此返回 3 & 3 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><strong>输入：</strong>num = 123\n<strong>输出：</strong>[5,25]\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre><strong>输入：</strong>num = 999\n<strong>输出：</strong>[40,25]\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 <= num <= 10^9</code></li>\n</ul>\n",
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"Find the divisors of n+1 and n+2.",
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