leetcode-problemset/leetcode-cn/originData/account-balance-after-rounded-purchase.json

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        "question": {
            "questionId": "2955",
            "questionFrontendId": "2806",
            "categoryTitle": "Algorithms",
            "boundTopicId": 2372231,
            "title": "Account Balance After Rounded Purchase",
            "titleSlug": "account-balance-after-rounded-purchase",
            "content": "<p>Initially, you have a bank account balance of <code>100</code> dollars.</p>\n\n<p>You are given an integer <code>purchaseAmount</code> representing the amount you will spend on a purchase in dollars.</p>\n\n<p>At the store where you will make the purchase, the purchase amount is rounded to the <strong>nearest multiple</strong> of <code>10</code>. In other words, you pay a <strong>non-negative</strong> amount, <code>roundedAmount</code>, such that <code>roundedAmount</code> is a multiple of <code>10</code> and <code>abs(roundedAmount - purchaseAmount)</code> is <strong>minimized</strong>.</p>\n\n<p>If there is more than one nearest multiple of <code>10</code>, the <strong>largest multiple</strong> is chosen.</p>\n\n<p>Return <em>an integer denoting your account balance after making a purchase worth </em><code>purchaseAmount</code><em> dollars from the store.</em></p>\n\n<p><strong>Note:</strong> <code>0</code> is considered to be a multiple of <code>10</code> in this problem.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> purchaseAmount = 9\n<strong>Output:</strong> 90\n<strong>Explanation:</strong> In this example, the nearest multiple of 10 to 9 is 10. Hence, your account balance becomes 100 - 10 = 90.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> purchaseAmount = 15\n<strong>Output:</strong> 80\n<strong>Explanation:</strong> In this example, there are two nearest multiples of 10 to 15: 10 and 20. So, the larger multiple, 20, is chosen.\nHence, your account balance becomes 100 - 20 = 80.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>0 &lt;= purchaseAmount &lt;= 100</code></li>\n</ul>\n",
            "translatedTitle": "取整购买后的账户余额",
            "translatedContent": "<p>一开始，你的银行账户里有&nbsp;<code>100</code>&nbsp;块钱。</p>\n\n<p>给你一个整数<code>purchaseAmount</code>&nbsp;，它表示你在一次购买中愿意支出的金额。</p>\n\n<p>在一个商店里，你进行一次购买，实际支出的金额会向 <strong>最近</strong>&nbsp;的&nbsp;<code>10</code>&nbsp;的 <strong>倍数</strong>&nbsp;取整。换句话说，你实际会支付一个&nbsp;<strong>非负</strong>&nbsp;金额&nbsp;<code>roundedAmount</code>&nbsp;，满足&nbsp;<code>roundedAmount</code>&nbsp;是&nbsp;<code>10</code>&nbsp;的倍数且&nbsp;<code>abs(roundedAmount - purchaseAmount)</code>&nbsp;的值 <strong>最小</strong>&nbsp;。</p>\n\n<p>如果存在多于一个最接近的 <code>10</code>&nbsp;的倍数，<strong>较大的倍数</strong>&nbsp;是你的实际支出金额。</p>\n\n<p>请你返回一个整数，表示你在愿意支出金额为<em>&nbsp;</em><code>purchaseAmount</code><em>&nbsp;</em>块钱的前提下，购买之后剩下的余额。</p>\n\n<p><strong>注意：</strong> <code>0</code>&nbsp;也是&nbsp;<code>10</code>&nbsp;的倍数。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><b>输入：</b>purchaseAmount = 9\n<b>输出：</b>90\n<b>解释：</b>这个例子中，最接近 9 的 10 的倍数是 10 。所以你的账户余额为 100 - 10 = 90 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><b>输入：</b>purchaseAmount = 15\n<b>输出：</b>80\n<b>解释：</b>这个例子中，有 2 个最接近 15 的 10 的倍数：10 和 20，较大的数 20 是你的实际开销。\n所以你的账户余额为 100 - 20 = 80 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>0 &lt;= purchaseAmount &lt;= 100</code></li>\n</ul>\n",
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                    "code": "class Solution {\npublic:\n    int accountBalanceAfterPurchase(int purchaseAmount) {\n        \n    }\n};",
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                    "code": "class Solution(object):\n    def accountBalanceAfterPurchase(self, purchaseAmount):\n        \"\"\"\n        :type purchaseAmount: int\n        :rtype: int\n        \"\"\"",
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                    "code": "# @param {Integer} purchase_amount\n# @return {Integer}\ndef account_balance_after_purchase(purchase_amount)\n\nend",
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            "hints": [
                "To determine the nearest multiple of 10, we can brute force the rounded amount since there are at most 100 options. In case of multiple nearest multiples, choose the largest.",
                "Another solution is observing that the rounded amount is floor((purchaseAmount + 5) / 10) * 10. Using this formula, we can calculate the account balance without having to brute force the rounded amount."
            ],
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