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{
"data": {
"question": {
"questionId": "1000146",
"questionFrontendId": "LCP 18",
"categoryTitle": "Algorithms",
"boundTopicId": 411213,
"title": "早餐组合",
"titleSlug": "2vYnGI",
"content": "English description is not available for the problem. Please switch to Chinese.",
"translatedTitle": "早餐组合",
"translatedContent": "小扣在秋日市集选择了一家早餐摊位,一维整型数组 `staple` 中记录了每种主食的价格,一维整型数组 `drinks` 中记录了每种饮料的价格。小扣的计划选择一份主食和一款饮料,且花费不超过 `x` 元。请返回小扣共有多少种购买方案。\r\n\r\n注意答案需要以 `1e9 + 7 (1000000007)` 为底取模,如:计算初始结果为:`1000000008`,请返回 `1`\r\n\r\n**示例 1**\r\n>输入:`staple = [10,20,5], drinks = [5,5,2], x = 15`\r\n>\r\n>输出:`6`\r\n>\r\n>解释:小扣有 6 种购买方案,所选主食与所选饮料在数组中对应的下标分别是:\r\n>第 1 种方案staple[0] + drinks[0] = 10 + 5 = 15\r\n>第 2 种方案staple[0] + drinks[1] = 10 + 5 = 15\r\n>第 3 种方案staple[0] + drinks[2] = 10 + 2 = 12\r\n>第 4 种方案staple[2] + drinks[0] = 5 + 5 = 10\r\n>第 5 种方案staple[2] + drinks[1] = 5 + 5 = 10\r\n>第 6 种方案staple[2] + drinks[2] = 5 + 2 = 7。\r\n\r\n**示例 2**\r\n>输入:`staple = [2,1,1], drinks = [8,9,5,1], x = 9`\r\n>\r\n>输出:`8`\r\n>\r\n>解释:小扣有 8 种购买方案,所选主食与所选饮料在数组中对应的下标分别是:\r\n>第 1 种方案staple[0] + drinks[2] = 2 + 5 = 7\r\n>第 2 种方案staple[0] + drinks[3] = 2 + 1 = 3\r\n>第 3 种方案staple[1] + drinks[0] = 1 + 8 = 9\r\n>第 4 种方案staple[1] + drinks[2] = 1 + 5 = 6\r\n>第 5 种方案staple[1] + drinks[3] = 1 + 1 = 2\r\n>第 6 种方案staple[2] + drinks[0] = 1 + 8 = 9\r\n>第 7 种方案staple[2] + drinks[2] = 1 + 5 = 6\r\n>第 8 种方案staple[2] + drinks[3] = 1 + 1 = 2\r\n\r\n**提示:**\r\n+ `1 <= staple.length <= 10^5`\r\n+ `1 <= drinks.length <= 10^5`\r\n+ `1 <= staple[i],drinks[i] <= 10^5`\r\n+ `1 <= x <= 2*10^5`",
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"difficulty": "Easy",
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"code": "class Solution {\npublic:\n int breakfastNumber(vector<int>& staple, vector<int>& drinks, int x) {\n\n }\n};",
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"code": "class Solution(object):\n def breakfastNumber(self, staple, drinks, x):\n \"\"\"\n :type staple: List[int]\n :type drinks: List[int]\n :type x: int\n :rtype: int\n \"\"\"",
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