mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-27 02:30:28 +08:00
177 lines
20 KiB
JSON
177 lines
20 KiB
JSON
{
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"questionId": "2427",
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"questionFrontendId": "2351",
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"categoryTitle": "Algorithms",
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"boundTopicId": 1689345,
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"title": "First Letter to Appear Twice",
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"titleSlug": "first-letter-to-appear-twice",
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"content": "<p>Given a string <code>s</code> consisting of lowercase English letters, return <em>the first letter to appear <strong>twice</strong></em>.</p>\n\n<p><strong>Note</strong>:</p>\n\n<ul>\n\t<li>A letter <code>a</code> appears twice before another letter <code>b</code> if the <strong>second</strong> occurrence of <code>a</code> is before the <strong>second</strong> occurrence of <code>b</code>.</li>\n\t<li><code>s</code> will contain at least one letter that appears twice.</li>\n</ul>\n\n<p> </p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = "abccbaacz"\n<strong>Output:</strong> "c"\n<strong>Explanation:</strong>\nThe letter 'a' appears on the indexes 0, 5 and 6.\nThe letter 'b' appears on the indexes 1 and 4.\nThe letter 'c' appears on the indexes 2, 3 and 7.\nThe letter 'z' appears on the index 8.\nThe letter 'c' is the first letter to appear twice, because out of all the letters the index of its second occurrence is the smallest.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = "abcdd"\n<strong>Output:</strong> "d"\n<strong>Explanation:</strong>\nThe only letter that appears twice is 'd' so we return 'd'.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>2 <= s.length <= 100</code></li>\n\t<li><code>s</code> consists of lowercase English letters.</li>\n\t<li><code>s</code> has at least one repeated letter.</li>\n</ul>\n",
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"translatedTitle": "第一个出现两次的字母",
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"translatedContent": "<p>给你一个由小写英文字母组成的字符串 <code>s</code> ,请你找出并返回第一个出现 <strong>两次</strong> 的字母。</p>\n\n<p><strong>注意:</strong></p>\n\n<ul>\n\t<li>如果 <code>a</code> 的 <strong>第二次</strong> 出现比 <code>b</code> 的 <strong>第二次</strong> 出现在字符串中的位置更靠前,则认为字母 <code>a</code> 在字母 <code>b</code> 之前出现两次。</li>\n\t<li><code>s</code> 包含至少一个出现两次的字母。</li>\n</ul>\n\n<p> </p>\n\n<p><strong>示例 1:</strong></p>\n\n<pre><strong>输入:</strong>s = \"abccbaacz\"\n<strong>输出:</strong>\"c\"\n<strong>解释:</strong>\n字母 'a' 在下标 0 、5 和 6 处出现。\n字母 'b' 在下标 1 和 4 处出现。\n字母 'c' 在下标 2 、3 和 7 处出现。\n字母 'z' 在下标 8 处出现。\n字母 'c' 是第一个出现两次的字母,因为在所有字母中,'c' 第二次出现的下标是最小的。\n</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<pre><strong>输入:</strong>s = \"abcdd\"\n<strong>输出:</strong>\"d\"\n<strong>解释:</strong>\n只有字母 'd' 出现两次,所以返回 'd' 。\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>2 <= s.length <= 100</code></li>\n\t<li><code>s</code> 由小写英文字母组成</li>\n\t<li><code>s</code> 包含至少一个重复字母</li>\n</ul>\n",
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"Iterate through the string from left to right. Keep track of the elements you have already seen in a set.",
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