mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-26 18:20:27 +08:00
161 lines
19 KiB
JSON
161 lines
19 KiB
JSON
{
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"questionId": "1000564",
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"questionFrontendId": "LCP 76",
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"categoryTitle": "Algorithms",
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"boundTopicId": 2238205,
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"title": "魔法棋盘",
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"translatedTitle": "魔法棋盘",
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"translatedContent": "在大小为 `n * m` 的棋盘中，有两种不同的棋子：黑色，红色。当两颗颜色不同的棋子同时满足以下两种情况时，将会产生魔法共鸣：\n- 两颗异色棋子在同一行或者同一列\n- 两颗异色棋子之间恰好只有一颗棋子\n\n由于棋盘上被施加了魔法禁制，棋盘上的部分格子变成问号。`chessboard[i][j]` 表示棋盘第 `i` 行 `j` 列的状态：\n- 若为 `.` ，表示当前格子确定为空\n- 若为 `B` ，表示当前格子确定为 黑棋\n- 若为 `R` ，表示当前格子确定为 红棋\n- 若为 `?` ，表示当前格子待定\n\n现在，探险家小扣的任务是确定所有问号位置的状态（留空/放黑棋/放红棋），使最终的棋盘上，任意两颗棋子间都 **无法** 产生共鸣。请返回可以满足上述条件的放置方案数量。\n\n**示例1：**\n> 输入：`n = 3, m = 3, chessboard = [\"..R\",\"..B\",\"?R?\"]`\n>\n> 输出：`5`\n>\n> 解释：给定的棋盘如图：\n>{:height=150px}\n> 所有符合题意的最终局面如图：\n>{:height=150px}\n\n**示例2：**\n> 输入：`n = 3, m = 3, chessboard = [\"?R?\",\"B?B\",\"?R?\"]`\n>\n> 输出：`105`\n\n**提示：**\n- `n == chessboard.length`\n- `m == chessboard[i].length`\n- `1 <= n*m <= 30`\n- `chessboard` 中仅包含 `\".\"、\"B\"、\"R\"、\"?\"`",
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"code": "class Solution(object):\n def getSchemeCount(self, n, m, chessboard):\n \"\"\"\n :type n: int\n :type m: int\n :type chessboard: List[str]\n :rtype: int\n \"\"\"",
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"code": "# @param {Integer} n\n# @param {Integer} m\n# @param {String[]} chessboard\n# @return {Integer}\ndef get_scheme_count(n, m, chessboard)\n\nend",
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"code": "defmodule Solution do\n @spec get_scheme_count(n :: integer, m :: integer, chessboard :: [String.t]) :: integer\n def get_scheme_count(n, m, chessboard) do\n\n end\nend",
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"sampleTestCase": "3\n3\n[\"..R\",\"..B\",\"?R?\"]",
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