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			34 lines
		
	
	
		
			1.6 KiB
		
	
	
	
		
			HTML
		
	
	
	
	
	
<p>You are given a <strong>0-indexed</strong> integer array <code>nums</code>. In one operation, select <strong>any</strong> non-negative integer <code>x</code> and an index <code>i</code>, then <strong>update</strong> <code>nums[i]</code> to be equal to <code>nums[i] AND (nums[i] XOR x)</code>.</p>
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<p>Note that <code>AND</code> is the bitwise AND operation and <code>XOR</code> is the bitwise XOR operation.</p>
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<p>Return <em>the <strong>maximum</strong> possible bitwise XOR of all elements of </em><code>nums</code><em> after applying the operation <strong>any number</strong> of times</em>.</p>
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<p> </p>
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<p><strong class="example">Example 1:</strong></p>
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<pre>
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<strong>Input:</strong> nums = [3,2,4,6]
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<strong>Output:</strong> 7
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<strong>Explanation:</strong> Apply the operation with x = 4 and i = 3, num[3] = 6 AND (6 XOR 4) = 6 AND 2 = 2.
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Now, nums = [3, 2, 4, 2] and the bitwise XOR of all the elements = 3 XOR 2 XOR 4 XOR 2 = 7.
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It can be shown that 7 is the maximum possible bitwise XOR.
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Note that other operations may be used to achieve a bitwise XOR of 7.</pre>
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<p><strong class="example">Example 2:</strong></p>
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<pre>
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<strong>Input:</strong> nums = [1,2,3,9,2]
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<strong>Output:</strong> 11
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<strong>Explanation:</strong> Apply the operation zero times.
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The bitwise XOR of all the elements = 1 XOR 2 XOR 3 XOR 9 XOR 2 = 11.
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It can be shown that 11 is the maximum possible bitwise XOR.</pre>
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<p> </p>
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<p><strong>Constraints:</strong></p>
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<ul>
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	<li><code>1 <= nums.length <= 10<sup>5</sup></code></li>
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	<li><code>0 <= nums[i] <= 10<sup>8</sup></code></li>
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</ul>
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