1
0
mirror of https://gitee.com/coder-xiaomo/leetcode-problemset synced 2025-01-10 18:48:13 +08:00
Code Issues Projects Releases Wiki Activity GitHub Gitee
leetcode-problemset/leetcode-cn/problem (Chinese)/生成斐波那契数列 [generate-fibonacci-sequence].html
2023-04-23 22:41:08 +08:00

38 lines
999 B
HTML
Raw Blame History

This file contains ambiguous Unicode characters

This file contains Unicode characters that might be confused with other characters. If you think that this is intentional, you can safely ignore this warning. Use the Escape button to reveal them.

<p>请你编写一个生成器函数,并返回一个可以生成 <strong>斐波那契数列</strong> 的生成器对象。</p>
<p><strong>斐波那契数列</strong> 的递推公式为 <code>X<sub>n</sub>&nbsp;= X<sub>n-1</sub>&nbsp;+ X<sub>n-2</sub></code></p>
<p>这个数列的前几个数字是 <code>0, 1, 1, 2, 3, 5, 8, 13</code>&nbsp;</p>
<p>&nbsp;</p>
<p><strong>示例 1</strong></p>
<pre>
<strong>输入:</strong>callCount = 5
<b>输出:</b>[0,1,1,2,3]
<strong>解释:</strong>
const gen = fibGenerator();
gen.next().value; // 0
gen.next().value; // 1
gen.next().value; // 1
gen.next().value; // 2
gen.next().value; // 3
</pre>
<p><strong>示例 2</strong></p>
<pre>
<b>输入:</b>callCount = 0
<strong>输出:</strong>[]
<b>解释:</b>gen.next() 永远不会被调用,所以什么也不会输出
</pre>
<p>&nbsp;</p>
<p><strong>提示:</strong></p>
<ul>
<li><code>0 &lt;= callCount &lt;= 50</code></li>
</ul>