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leetcode-problemset/leetcode-cn/problem (Chinese)/实现一个魔法字典 [implement-magic-dictionary].html
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<p>设计一个使用单词列表进行初始化的数据结构,单词列表中的单词 <strong>互不相同</strong> 。 如果给出一个单词,请判定能否只将这个单词中<strong>一个</strong>字母换成另一个字母,使得所形成的新单词存在于你构建的字典中。</p>
<p>实现 <code>MagicDictionary</code> 类:</p>
<ul>
<li><code>MagicDictionary()</code> 初始化对象</li>
<li><code>void buildDict(String[] dictionary)</code> 使用字符串数组 <code>dictionary</code> 设定该数据结构,<code>dictionary</code> 中的字符串互不相同</li>
<li><code>bool search(String searchWord)</code> 给定一个字符串 <code>searchWord</code> ,判定能否只将字符串中<strong> 一个 </strong>字母换成另一个字母,使得所形成的新字符串能够与字典中的任一字符串匹配。如果可以,返回 <code>true</code> ;否则,返回 <code>false</code></li>
</ul>
<p> </p>
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<div class="original__bRMd">
<div>
<p><strong>示例:</strong></p>
<pre>
<strong>输入</strong>
["MagicDictionary", "buildDict", "search", "search", "search", "search"]
[[], [["hello", "leetcode"]], ["hello"], ["hhllo"], ["hell"], ["leetcoded"]]
<strong>输出</strong>
[null, null, false, true, false, false]
<strong>解释</strong>
MagicDictionary magicDictionary = new MagicDictionary();
magicDictionary.buildDict(["hello", "leetcode"]);
magicDictionary.search("hello"); // 返回 False
magicDictionary.search("hhllo"); // 将第二个 'h' 替换为 'e' 可以匹配 "hello" ,所以返回 True
magicDictionary.search("hell"); // 返回 False
magicDictionary.search("leetcoded"); // 返回 False
</pre>
<p> </p>
<p><strong>提示:</strong></p>
<ul>
<li><code>1 <= dictionary.length <= 100</code></li>
<li><code>1 <= dictionary[i].length <= 100</code></li>
<li><code>dictionary[i]</code> 仅由小写英文字母组成</li>
<li><code>dictionary</code> 中的所有字符串 <strong>互不相同</strong></li>
<li><code>1 <= searchWord.length <= 100</code></li>
<li><code>searchWord</code> 仅由小写英文字母组成</li>
<li><code>buildDict</code> 仅在 <code>search</code> 之前调用一次</li>
<li>最多调用 <code>100</code><code>search</code></li>
</ul>
</div>
</div>
</div>