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51 lines
1.5 KiB
HTML
51 lines
1.5 KiB
HTML
<p>创建一个名为 <code>ArrayWrapper</code> 的类，它在其构造函数中接受一个整数数组作为参数。该类应具有以下两个特性：</p>
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<ul>
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<li>当使用 <code>+</code> 运算符将两个该类的实例相加时，结果值为两个数组中所有元素的总和。</li>
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<li>当在实例上调用 <code>String()</code> 函数时，它将返回一个由逗号分隔的括在方括号中的字符串。例如，<code>[1,2,3]</code> 。</li>
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</ul>
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<p> </p>
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<p><strong class="example">示例 1：</strong></p>
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<pre>
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<b>输入：</b>nums = [[1,2],[3,4]], operation = "Add"
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<b>输出：</b>10
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<b>解释：</b>
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const obj1 = new ArrayWrapper([1,2]);
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const obj2 = new ArrayWrapper([3,4]);
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obj1 + obj2; // 10
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</pre>
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<p><strong class="example">示例 2：</strong></p>
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<pre>
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<b>输入：</b>nums = [[23,98,42,70]], operation = "String"
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<b>输出：</b>"[23,98,42,70]"
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<strong>解释：</strong>
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const obj = new ArrayWrapper([23,98,42,70]);
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String(obj); // "[23,98,42,70]"
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</pre>
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<p><strong class="example">示例 3：</strong></p>
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<pre>
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<b>输入：</b>nums = [[],[]], operation = "Add"
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<b>输出：</b>0
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<strong>解释：</strong>
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const obj1 = new ArrayWrapper([]);
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const obj2 = new ArrayWrapper([]);
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obj1 + obj2; // 0
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</pre>
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<p> </p>
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<p><b>提示：</b></p>
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<ul>
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<li><code>0 <= nums.length <= 1000</code></li>
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<li><code>0 <= nums[i] <= 1000</code></li>
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<li><code>注意：nums 是传递给构造函数的数组。</code></li>
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</ul>
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