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"questionFrontendId": "2310",
"categoryTitle": "Algorithms",
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"title": "Sum of Numbers With Units Digit K",
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"content": "<p>Given two integers <code>num</code> and <code>k</code>, consider a set of positive integers with the following properties:</p>\n\n<ul>\n\t<li>The units digit of each integer is <code>k</code>.</li>\n\t<li>The sum of the integers is <code>num</code>.</li>\n</ul>\n\n<p>Return <em>the <strong>minimum</strong> possible size of such a set, or </em><code>-1</code><em> if no such set exists.</em></p>\n\n<p>Note:</p>\n\n<ul>\n\t<li>The set can contain multiple instances of the same integer, and the sum of an empty set is considered <code>0</code>.</li>\n\t<li>The <strong>units digit</strong> of a number is the rightmost digit of the number.</li>\n</ul>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> num = 58, k = 9\n<strong>Output:</strong> 2\n<strong>Explanation:</strong>\nOne valid set is [9,49], as the sum is 58 and each integer has a units digit of 9.\nAnother valid set is [19,39].\nIt can be shown that 2 is the minimum possible size of a valid set.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> num = 37, k = 2\n<strong>Output:</strong> -1\n<strong>Explanation:</strong> It is not possible to obtain a sum of 37 using only integers that have a units digit of 2.\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> num = 0, k = 7\n<strong>Output:</strong> 0\n<strong>Explanation:</strong> The sum of an empty set is considered 0.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>0 &lt;= num &lt;= 3000</code></li>\n\t<li><code>0 &lt;= k &lt;= 9</code></li>\n</ul>\n",
"translatedTitle": "个位数字为 K 的整数之和",
"translatedContent": "<p>给你两个整数 <code>num</code> 和 <code>k</code> ,考虑具有以下属性的正整数多重集:</p>\n\n<ul>\n\t<li>每个整数个位数字都是 <code>k</code> 。</li>\n\t<li>所有整数之和是 <code>num</code> 。</li>\n</ul>\n\n<p>返回该多重集的最小大小,如果不存在这样的多重集,返回<em> </em><code>-1</code> 。</p>\n\n<p>注意:</p>\n\n<ul>\n\t<li>多重集与集合类似,但多重集可以包含多个同一整数,空多重集的和为 <code>0</code> 。</li>\n\t<li><strong>个位数字</strong> 是数字最右边的数位。</li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<pre>\n<strong>输入:</strong>num = 58, k = 9\n<strong>输出:</strong>2\n<strong>解释:</strong>\n多重集 [9,49] 满足题目条件,和为 58 且每个整数的个位数字是 9 。\n另一个满足条件的多重集是 [19,39] 。\n可以证明 2 是满足题目条件的多重集的最小长度。\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>num = 37, k = 2\n<strong>输出:</strong>-1\n<strong>解释:</strong>个位数字为 2 的整数无法相加得到 37 。</pre>\n\n<p><strong>示例 3</strong></p>\n\n<pre>\n<strong>输入:</strong>num = 0, k = 7\n<strong>输出:</strong>0\n<strong>解释:</strong>空多重集的和为 0 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>0 &lt;= num &lt;= 3000</code></li>\n\t<li><code>0 &lt;= k &lt;= 9</code></li>\n</ul>\n",
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"Create a method that takes an integer x as a parameter. This method returns the minimum possible size of a set where each number has units digit k and the sum of the numbers in the set is x."
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