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"categoryTitle": "Algorithms",
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"title": "Split Array Largest Sum",
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"content": "<p>Given an array <code>nums</code> which consists of non-negative integers and an integer <code>m</code>, you can split the array into <code>m</code> non-empty continuous subarrays.</p>\n\n<p>Write an algorithm to minimize the largest sum among these <code>m</code> subarrays.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [7,2,5,10,8], m = 2\n<strong>Output:</strong> 18\n<strong>Explanation:</strong>\nThere are four ways to split nums into two subarrays.\nThe best way is to split it into [7,2,5] and [10,8],\nwhere the largest sum among the two subarrays is only 18.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,2,3,4,5], m = 2\n<strong>Output:</strong> 9\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,4,4], m = 3\n<strong>Output:</strong> 4\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 1000</code></li>\n\t<li><code>0 &lt;= nums[i] &lt;= 10<sup>6</sup></code></li>\n\t<li><code>1 &lt;= m &lt;= min(50, nums.length)</code></li>\n</ul>\n",
"translatedTitle": "分割数组的最大值",
"translatedContent": "<p>给定一个非负整数数组 <code>nums</code> 和一个整数&nbsp;<code>m</code> ,你需要将这个数组分成&nbsp;<code>m</code><em>&nbsp;</em>个非空的连续子数组。</p>\n\n<p>设计一个算法使得这&nbsp;<code>m</code><em>&nbsp;</em>个子数组各自和的最大值最小。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<pre>\n<strong>输入:</strong>nums = [7,2,5,10,8], m = 2\n<strong>输出:</strong>18\n<strong>解释:</strong>\n一共有四种方法将 nums 分割为 2 个子数组。 \n其中最好的方式是将其分为 [7,2,5] 和 [10,8] 。\n因为此时这两个子数组各自的和的最大值为18在所有情况中最小。</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>nums = [1,2,3,4,5], m = 2\n<strong>输出:</strong>9\n</pre>\n\n<p><strong>示例 3</strong></p>\n\n<pre>\n<strong>输入:</strong>nums = [1,4,4], m = 3\n<strong>输出:</strong>4\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 1000</code></li>\n\t<li><code>0 &lt;= nums[i] &lt;= 10<sup>6</sup></code></li>\n\t<li><code>1 &lt;= m &lt;= min(50, nums.length)</code></li>\n</ul>\n",
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