leetcode-problemset/leetcode-cn/originData/smallest-rotation-with-highest-score.json

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            "title": "Smallest Rotation with Highest Score",
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            "content": "<p>You are given an array <code>nums</code>. You can rotate it by a non-negative integer <code>k</code> so that the array becomes <code>[nums[k], nums[k + 1], ... nums[nums.length - 1], nums[0], nums[1], ..., nums[k-1]]</code>. Afterward, any entries that are less than or equal to their index are worth one point.</p>\n\n<ul>\n\t<li>For example, if we have <code>nums = [2,4,1,3,0]</code>, and we rotate by <code>k = 2</code>, it becomes <code>[1,3,0,2,4]</code>. This is worth <code>3</code> points because <code>1 &gt; 0</code> [no points], <code>3 &gt; 1</code> [no points], <code>0 &lt;= 2</code> [one point], <code>2 &lt;= 3</code> [one point], <code>4 &lt;= 4</code> [one point].</li>\n</ul>\n\n<p>Return <em>the rotation index </em><code>k</code><em> that corresponds to the highest score we can achieve if we rotated </em><code>nums</code><em> by it</em>. If there are multiple answers, return the smallest such index <code>k</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [2,3,1,4,0]\n<strong>Output:</strong> 3\n<strong>Explanation:</strong> Scores for each k are listed below: \nk = 0,  nums = [2,3,1,4,0],    score 2\nk = 1,  nums = [3,1,4,0,2],    score 3\nk = 2,  nums = [1,4,0,2,3],    score 3\nk = 3,  nums = [4,0,2,3,1],    score 4\nk = 4,  nums = [0,2,3,1,4],    score 3\nSo we should choose k = 3, which has the highest score.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,3,0,2,4]\n<strong>Output:</strong> 0\n<strong>Explanation:</strong> nums will always have 3 points no matter how it shifts.\nSo we will choose the smallest k, which is 0.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>0 &lt;= nums[i] &lt; nums.length</code></li>\n</ul>\n",
            "translatedTitle": "得分最高的最小轮调",
            "translatedContent": "<p>给你一个数组&nbsp;<code>nums</code>，我们可以将它按一个非负整数 <code>k</code> 进行轮调，这样可以使数组变为&nbsp;<code>[nums[k], nums[k + 1], ... nums[nums.length - 1], nums[0], nums[1], ..., nums[k-1]]</code>&nbsp;的形式。此后，任何值小于或等于其索引的项都可以记作一分。</p>\n\n<ul>\n\t<li>例如，数组为&nbsp;<code>nums = [2,4,1,3,0]</code>，我们按&nbsp;<code>k = 2</code>&nbsp;进行轮调后，它将变成&nbsp;<code>[1,3,0,2,4]</code>。这将记为 <code>3</code> 分，因为 <code>1 &gt; 0</code> [不计分]、<code>3 &gt; 1</code> [不计分]、<code>0 &lt;= 2</code> [计 1 分]、<code>2 &lt;= 3</code> [计 1 分]，<code>4 &lt;= 4</code> [计 1 分]。</li>\n</ul>\n\n<p>在所有可能的轮调中，返回我们所能得到的最高分数对应的轮调下标 <code>k</code> 。如果有多个答案，返回满足条件的最小的下标 <code>k</code> 。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [2,3,1,4,0]\n<strong>输出：</strong>3\n<strong>解释：</strong>\n下面列出了每个 k 的得分：\nk = 0,  nums = [2,3,1,4,0],    score 2\nk = 1,  nums = [3,1,4,0,2],    score 3\nk = 2,  nums = [1,4,0,2,3],    score 3\nk = 3,  nums = [4,0,2,3,1],    score 4\nk = 4,  nums = [0,2,3,1,4],    score 3\n所以我们应当选择&nbsp;k = 3，得分最高。</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [1,3,0,2,4]\n<strong>输出：</strong>0\n<strong>解释：</strong>\nnums 无论怎么变化总是有 3 分。\n所以我们将选择最小的 k，即 0。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>0 &lt;= nums[i] &lt; nums.length</code></li>\n</ul>\n",
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