leetcode-problemset/leetcode-cn/originData/replace-elements-in-an-array.json

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        "question": {
            "questionId": "2388",
            "questionFrontendId": "2295",
            "categoryTitle": "Algorithms",
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            "title": "Replace Elements in an Array",
            "titleSlug": "replace-elements-in-an-array",
            "content": "<p>You are given a <strong>0-indexed</strong> array <code>nums</code> that consists of <code>n</code> <strong>distinct</strong> positive integers. Apply <code>m</code> operations to this array, where in the <code>i<sup>th</sup></code> operation you replace the number <code>operations[i][0]</code> with <code>operations[i][1]</code>.</p>\n\n<p>It is guaranteed that in the <code>i<sup>th</sup></code> operation:</p>\n\n<ul>\n\t<li><code>operations[i][0]</code> <strong>exists</strong> in <code>nums</code>.</li>\n\t<li><code>operations[i][1]</code> does <strong>not</strong> exist in <code>nums</code>.</li>\n</ul>\n\n<p>Return <em>the array obtained after applying all the operations</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,2,4,6], operations = [[1,3],[4,7],[6,1]]\n<strong>Output:</strong> [3,2,7,1]\n<strong>Explanation:</strong> We perform the following operations on nums:\n- Replace the number 1 with 3. nums becomes [<u><strong>3</strong></u>,2,4,6].\n- Replace the number 4 with 7. nums becomes [3,2,<u><strong>7</strong></u>,6].\n- Replace the number 6 with 1. nums becomes [3,2,7,<u><strong>1</strong></u>].\nWe return the final array [3,2,7,1].\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,2], operations = [[1,3],[2,1],[3,2]]\n<strong>Output:</strong> [2,1]\n<strong>Explanation:</strong> We perform the following operations to nums:\n- Replace the number 1 with 3. nums becomes [<u><strong>3</strong></u>,2].\n- Replace the number 2 with 1. nums becomes [3,<u><strong>1</strong></u>].\n- Replace the number 3 with 2. nums becomes [<u><strong>2</strong></u>,1].\nWe return the array [2,1].\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == nums.length</code></li>\n\t<li><code>m == operations.length</code></li>\n\t<li><code>1 &lt;= n, m &lt;= 10<sup>5</sup></code></li>\n\t<li>All the values of <code>nums</code> are <strong>distinct</strong>.</li>\n\t<li><code>operations[i].length == 2</code></li>\n\t<li><code>1 &lt;= nums[i], operations[i][0], operations[i][1] &lt;= 10<sup>6</sup></code></li>\n\t<li><code>operations[i][0]</code> will exist in <code>nums</code> when applying the <code>i<sup>th</sup></code> operation.</li>\n\t<li><code>operations[i][1]</code> will not exist in <code>nums</code> when applying the <code>i<sup>th</sup></code> operation.</li>\n</ul>\n",
            "translatedTitle": "替换数组中的元素",
            "translatedContent": "<p>给你一个下标从 <strong>0</strong>&nbsp;开始的数组&nbsp;<code>nums</code>&nbsp;，它包含 <code>n</code>&nbsp;个 <strong>互不相同</strong>&nbsp;的正整数。请你对这个数组执行 <code>m</code>&nbsp;个操作，在第 <code>i</code>&nbsp;个操作中，你需要将数字&nbsp;<code>operations[i][0]</code> 替换成&nbsp;<code>operations[i][1]</code>&nbsp;。</p>\n\n<p>题目保证在第 <code>i</code>&nbsp;个操作中：</p>\n\n<ul>\n\t<li><code>operations[i][0]</code>&nbsp;在&nbsp;<code>nums</code>&nbsp;中存在。</li>\n\t<li><code>operations[i][1]</code>&nbsp;在&nbsp;<code>nums</code>&nbsp;中不存在。</li>\n</ul>\n\n<p>请你返回执行完所有操作后的数组。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><b>输入：</b>nums = [1,2,4,6], operations = [[1,3],[4,7],[6,1]]\n<b>输出：</b>[3,2,7,1]\n<b>解释：</b>我们对 nums 执行以下操作：\n- 将数字 1 替换为 3 。nums 变为 [<em><strong>3</strong></em>,2,4,6] 。\n- 将数字 4 替换为 7 。nums 变为 [3,2,<em><strong>7</strong></em>,6] 。\n- 将数字 6 替换为 1 。nums 变为 [3,2,7,<em><strong>1</strong></em>] 。\n返回最终数组 [3,2,7,1] 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><b>输入：</b>nums = [1,2], operations = [[1,3],[2,1],[3,2]]\n<b>输出：</b>[2,1]\n<b>解释：</b>我们对 nums 执行以下操作：\n- 将数字 1 替换为 3 。nums 变为 [<em><strong>3</strong></em>,2] 。\n- 将数字 2 替换为 1 。nums 变为 [3,<em><strong>1</strong></em>] 。\n- 将数字 3 替换为 2 。nums 变为 [<em><strong>2</strong></em>,1] 。\n返回最终数组 [2,1] 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>n == nums.length</code></li>\n\t<li><code>m == operations.length</code></li>\n\t<li><code>1 &lt;= n, m &lt;= 10<sup>5</sup></code></li>\n\t<li><code>nums</code>&nbsp;中所有数字 <strong>互不相同</strong>&nbsp;。</li>\n\t<li><code>operations[i].length == 2</code></li>\n\t<li><code>1 &lt;= nums[i], operations[i][0], operations[i][1] &lt;= 10<sup>6</sup></code></li>\n\t<li>在执行第&nbsp;<code>i</code> 个操作时，<code>operations[i][0]</code>&nbsp;在&nbsp;<code>nums</code>&nbsp;中存在。</li>\n\t<li>在执行第&nbsp;<code>i</code>&nbsp;个操作时，<code>operations[i][1]</code>&nbsp;在&nbsp;<code>nums</code>&nbsp;中不存在。</li>\n</ul>\n",
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