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leetcode-problemset/leetcode-cn/originData/reduction-operations-to-make-the-array-elements-equal.json
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{
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"question": {
"questionId": "2016",
"questionFrontendId": "1887",
"categoryTitle": "Algorithms",
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"title": "Reduction Operations to Make the Array Elements Equal",
"titleSlug": "reduction-operations-to-make-the-array-elements-equal",
"content": "<p>Given an integer array <code>nums</code>, your goal is to make all elements in <code>nums</code> equal. To complete one operation, follow these steps:</p>\n\n<ol>\n\t<li>Find the <strong>largest</strong> value in <code>nums</code>. Let its index be <code>i</code> (<strong>0-indexed</strong>) and its value be <code>largest</code>. If there are multiple elements with the largest value, pick the smallest <code>i</code>.</li>\n\t<li>Find the <strong>next largest</strong> value in <code>nums</code> <strong>strictly smaller</strong> than <code>largest</code>. Let its value be <code>nextLargest</code>.</li>\n\t<li>Reduce <code>nums[i]</code> to <code>nextLargest</code>.</li>\n</ol>\n\n<p>Return <em>the number of operations to make all elements in </em><code>nums</code><em> equal</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [5,1,3]\n<strong>Output:</strong> 3\n<strong>Explanation:</strong>&nbsp;It takes 3 operations to make all elements in nums equal:\n1. largest = 5 at index 0. nextLargest = 3. Reduce nums[0] to 3. nums = [<u>3</u>,1,3].\n2. largest = 3 at index 0. nextLargest = 1. Reduce nums[0] to 1. nums = [<u>1</u>,1,3].\n3. largest = 3 at index 2. nextLargest = 1. Reduce nums[2] to 1. nums = [1,1,<u>1</u>].\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,1,1]\n<strong>Output:</strong> 0\n<strong>Explanation:</strong>&nbsp;All elements in nums are already equal.\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,1,2,2,3]\n<strong>Output:</strong> 4\n<strong>Explanation:</strong>&nbsp;It takes 4 operations to make all elements in nums equal:\n1. largest = 3 at index 4. nextLargest = 2. Reduce nums[4] to 2. nums = [1,1,2,2,<u>2</u>].\n2. largest = 2 at index 2. nextLargest = 1. Reduce nums[2] to 1. nums = [1,1,<u>1</u>,2,2].\n3. largest = 2 at index 3. nextLargest = 1. Reduce nums[3] to 1. nums = [1,1,1,<u>1</u>,2].\n4. largest = 2 at index 4. nextLargest = 1. Reduce nums[4] to 1. nums = [1,1,1,1,<u>1</u>].\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 5 * 10<sup>4</sup></code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 5 * 10<sup>4</sup></code></li>\n</ul>\n",
"translatedTitle": "使数组元素相等的减少操作次数",
"translatedContent": "<p>给你一个整数数组 <code>nums</code> ,你的目标是令 <code>nums</code> 中的所有元素相等。完成一次减少操作需要遵照下面的几个步骤:</p>\n\n<ol>\n\t<li>找出 <code>nums</code> 中的 <strong>最大</strong> 值。记这个值为 <code>largest</code> 并取其下标 <code>i</code> <strong>下标从 0 开始计数</strong>)。如果有多个元素都是最大值,则取最小的 <code>i</code> 。</li>\n\t<li>找出 <code>nums</code> 中的 <strong>下一个最大</strong> 值,这个值 <strong>严格小于</strong> <code>largest</code> ,记为 <code>nextLargest</code> 。</li>\n\t<li>将 <code>nums[i]</code> 减少到 <code>nextLargest</code> 。</li>\n</ol>\n\n<p>返回使<em> </em><code>nums</code><em> </em>中的所有元素相等的操作次数。</p>\n\n<p> </p>\n\n<p><strong>示例 1</strong></p>\n\n<pre>\n<strong>输入:</strong>nums = [5,1,3]\n<strong>输出:</strong>3\n<strong>解释:</strong>需要 3 次操作使 nums 中的所有元素相等:\n1. largest = 5 下标为 0 。nextLargest = 3 。将 nums[0] 减少到 3 。nums = [<strong>3</strong>,1,3] 。\n2. largest = 3 下标为 0 。nextLargest = 1 。将 nums[0] 减少到 1 。nums = [<strong>1</strong>,1,3] 。\n3. largest = 3 下标为 2 。nextLargest = 1 。将 nums[2] 减少到 1 。nums = [<strong>1</strong>,1,<strong>1</strong>] 。\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>nums = [1,1,1]\n<strong>输出:</strong>0\n<strong>解释:</strong>nums 中的所有元素已经是相等的。\n</pre>\n\n<p><strong>示例 3</strong></p>\n\n<pre>\n<strong>输入:</strong>nums = [1,1,2,2,3]\n<strong>输出:</strong>4\n<strong>解释:</strong>需要 4 次操作使 nums 中的所有元素相等:\n1. largest = 3 下标为 4 。nextLargest = 2 。将 nums[4] 减少到 2 。nums = [1,1,2,2,<strong>2</strong>] 。\n2. largest = 2 下标为 2 。nextLargest = 1 。将 nums[2] 减少到 1 。nums = [1,1,<strong>1</strong>,2,2] 。 \n3. largest = 2 下标为 3 。nextLargest = 1 。将 nums[3] 减少到 1 。nums = [1,1,1,<strong>1</strong>,2] 。 \n4. largest = 2 下标为 4 。nextLargest = 1 。将 nums[4] 减少到 1 。nums = [1,1,1,1,<strong>1</strong>] 。\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 <= nums.length <= 5 * 10<sup>4</sup></code></li>\n\t<li><code>1 <= nums[i] <= 5 * 10<sup>4</sup></code></li>\n</ul>\n",
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