leetcode-problemset/leetcode-cn/originData/number-of-zero-filled-subarrays.json

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        "question": {
            "questionId": "2432",
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            "categoryTitle": "Algorithms",
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            "title": "Number of Zero-Filled Subarrays",
            "titleSlug": "number-of-zero-filled-subarrays",
            "content": "<p>Given an integer array <code>nums</code>, return <em>the number of <strong>subarrays</strong> filled with </em><code>0</code>.</p>\n\n<p>A <strong>subarray</strong> is a contiguous non-empty sequence of elements within an array.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,3,0,0,2,0,0,4]\n<strong>Output:</strong> 6\n<strong>Explanation:</strong> \nThere are 4 occurrences of [0] as a subarray.\nThere are 2 occurrences of [0,0] as a subarray.\nThere is no occurrence of a subarray with a size more than 2 filled with 0. Therefore, we return 6.</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [0,0,0,2,0,0]\n<strong>Output:</strong> 9\n<strong>Explanation:\n</strong>There are 5 occurrences of [0] as a subarray.\nThere are 3 occurrences of [0,0] as a subarray.\nThere is 1 occurrence of [0,0,0] as a subarray.\nThere is no occurrence of a subarray with a size more than 3 filled with 0. Therefore, we return 9.\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [2,10,2019]\n<strong>Output:</strong> 0\n<strong>Explanation:</strong> There is no subarray filled with 0. Therefore, we return 0.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>-10<sup>9</sup> &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
            "translatedTitle": "全 0 子数组的数目",
            "translatedContent": "<p>给你一个整数数组&nbsp;<code>nums</code>&nbsp;，返回全部为&nbsp;<code>0</code>&nbsp;的&nbsp;<strong>子数组</strong>&nbsp;数目。</p>\n\n<p><strong>子数组</strong>&nbsp;是一个数组中一段连续非空元素组成的序列。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><b>输入：</b>nums = [1,3,0,0,2,0,0,4]\n<b>输出：</b>6\n<b>解释：</b>\n子数组 [0] 出现了 4 次。\n子数组 [0,0] 出现了 2 次。\n不存在长度大于 2 的全 0 子数组，所以我们返回 6 。</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><b>输入：</b>nums = [0,0,0,2,0,0]\n<b>输出：</b>9\n<strong>解释：\n</strong>子数组 [0] 出现了 5 次。\n子数组 [0,0] 出现了 3 次。\n子数组 [0,0,0] 出现了 1 次。\n不存在长度大于 3 的全 0 子数组，所以我们返回 9 。\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre><b>输入：</b>nums = [2,10,2019]\n<b>输出：</b>0\n<b>解释：</b>没有全 0 子数组，所以我们返回 0 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>-10<sup>9</sup> &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
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            "hints": [
                "For each zero, you can calculate the number of zero-filled subarrays that end on that index, which is the number of consecutive zeros behind the current element + 1.",
                "Maintain the number of consecutive zeros behind the current element, count the number of zero-filled subarrays that end on each index, sum it up to get the answer."
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