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leetcode-problemset/leetcode-cn/originData/number-of-digit-one.json
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{
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"categoryTitle": "Algorithms",
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"title": "Number of Digit One",
"titleSlug": "number-of-digit-one",
"content": "<p>Given an integer <code>n</code>, count <em>the total number of digit </em><code>1</code><em> appearing in all non-negative integers less than or equal to</em> <code>n</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 13\n<strong>Output:</strong> 6\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 0\n<strong>Output:</strong> 0\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>0 &lt;= n &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
"translatedTitle": "数字 1 的个数",
"translatedContent": "<p>给定一个整数 <code>n</code>,计算所有小于等于 <code>n</code> 的非负整数中数字 <code>1</code> 出现的个数。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<pre>\n<strong>输入:</strong>n = 13\n<strong>输出:</strong>6\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>n = 0\n<strong>输出:</strong>0\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>0 &lt;= n &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
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