leetcode-problemset/leetcode-cn/originData/number-of-adjacent-elements-with-the-same-color.json

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        "question": {
            "questionId": "2779",
            "questionFrontendId": "2672",
            "categoryTitle": "Algorithms",
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            "title": "Number of Adjacent Elements With the Same Color",
            "titleSlug": "number-of-adjacent-elements-with-the-same-color",
            "content": "<p>There is a <strong>0-indexed</strong> array <code>nums</code> of length <code>n</code>. Initially, all elements are <strong>uncolored </strong>(has a value of <code>0</code>).</p>\n\n<p>You are given a 2D integer array <code>queries</code> where <code>queries[i] = [index<sub>i</sub>, color<sub>i</sub>]</code>.</p>\n\n<p>For each query, you color the index <code>index<sub>i</sub></code> with the color <code>color<sub>i</sub></code> in the array <code>nums</code>.</p>\n\n<p>Return <em>an array </em><code>answer</code><em> of the same length as </em><code>queries</code><em> where </em><code>answer[i]</code><em> is the number of adjacent elements with the same color <strong>after</strong> the </em><code>i<sup>th</sup></code><em> query</em>.</p>\n\n<p>More formally, <code>answer[i]</code> is the number of indices <code>j</code>, such that <code>0 &lt;= j &lt; n - 1</code> and <code>nums[j] == nums[j + 1]</code> and <code>nums[j] != 0</code> after the <code>i<sup>th</sup></code> query.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 4, queries = [[0,2],[1,2],[3,1],[1,1],[2,1]]\n<strong>Output:</strong> [0,1,1,0,2]\n<strong>Explanation:</strong> Initially array nums = [0,0,0,0], where 0 denotes uncolored elements of the array.\n- After the 1<sup>st</sup> query nums = [2,0,0,0]. The count of adjacent elements with the same color is 0.\n- After the 2<sup>nd</sup> query nums = [2,2,0,0]. The count of adjacent elements with the same color is 1.\n- After the 3<sup>rd</sup>&nbsp;query nums = [2,2,0,1]. The count of adjacent elements with the same color is 1.\n- After the 4<sup>th</sup>&nbsp;query nums = [2,1,0,1]. The count of adjacent elements with the same color is 0.\n- After the 5<sup>th</sup>&nbsp;query nums = [2,1,1,1]. The count of adjacent elements with the same color is 2.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 1, queries = [[0,100000]]\n<strong>Output:</strong> [0]\n<strong>Explanation:</strong> Initially array nums = [0], where 0 denotes uncolored elements of the array.\n- After the 1<sup>st</sup> query nums = [100000]. The count of adjacent elements with the same color is 0.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= queries.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>queries[i].length&nbsp;== 2</code></li>\n\t<li><code>0 &lt;= index<sub>i</sub>&nbsp;&lt;= n - 1</code></li>\n\t<li><code>1 &lt;=&nbsp; color<sub>i</sub>&nbsp;&lt;= 10<sup>5</sup></code></li>\n</ul>\n",
            "translatedTitle": "有相同颜色的相邻元素数目",
            "translatedContent": "<p>给你一个下标从 <strong>0</strong>&nbsp;开始、长度为 <code>n</code>&nbsp;的数组&nbsp;<code>nums</code>&nbsp;。一开始，所有元素都是 <strong>未染色</strong>&nbsp;（值为 <code>0</code>&nbsp;）的。</p>\n\n<p>给你一个二维整数数组&nbsp;<code>queries</code>&nbsp;，其中&nbsp;<code>queries[i] = [index<sub>i</sub>, color<sub>i</sub>]</code>&nbsp;。</p>\n\n<p>对于每个操作，你需要将数组 <code>nums</code>&nbsp;中下标为&nbsp;<code>index<sub>i</sub></code>&nbsp;的格子染色为&nbsp;<code>color<sub>i</sub></code>&nbsp;。</p>\n\n<p>请你返回一个长度与 <code>queries</code>&nbsp;相等的数组<em>&nbsp;</em><code>answer</code><em>&nbsp;</em>，其中<em>&nbsp;</em><code>answer[i]</code>是前 <code>i</code>&nbsp;个操作&nbsp;<strong>之后</strong>&nbsp;，相邻元素颜色相同的数目。</p>\n\n<p>更正式的，<code>answer[i]</code>&nbsp;是执行完前 <code>i</code>&nbsp;个操作后，<code>0 &lt;= j &lt; n - 1</code>&nbsp;的下标 <code>j</code>&nbsp;中，满足&nbsp;<code>nums[j] == nums[j + 1]</code> 且&nbsp;<code>nums[j] != 0</code>&nbsp;的数目。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<b>输入：</b>n = 4, queries = [[0,2],[1,2],[3,1],[1,1],[2,1]]\n<b>输出：</b>[0,1,1,0,2]\n<b>解释：</b>一开始数组 nums = [0,0,0,0] ，0 表示数组中还没染色的元素。\n- 第 1 个操作后，nums = [2,0,0,0] 。相邻元素颜色相同的数目为 0 。\n- 第 2 个操作后，nums = [2,2,0,0] 。相邻元素颜色相同的数目为 1 。\n- 第 3 个操作后，nums = [2,2,0,1] 。相邻元素颜色相同的数目为 1 。\n- 第 4 个操作后，nums = [2,1,0,1] 。相邻元素颜色相同的数目为 0 。\n- 第 5 个操作后，nums = [2,1,1,1] 。相邻元素颜色相同的数目为 2 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<b>输入：</b>n = 1, queries = [[0,100000]]\n<b>输出：</b>[0]\n<b>解释：</b>一开始数组 nums = [0] ，0 表示数组中还没染色的元素。\n- 第 1 个操作后，nums = [100000] 。相邻元素颜色相同的数目为 0 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= queries.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>queries[i].length&nbsp;== 2</code></li>\n\t<li><code>0 &lt;= index<sub>i</sub>&nbsp;&lt;= n - 1</code></li>\n\t<li><code>1 &lt;=&nbsp; color<sub>i</sub>&nbsp;&lt;= 10<sup>5</sup></code></li>\n</ul>\n",
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                "Since at each query, only one element is being recolored, we just need to focus on its neighbors.",
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