leetcode-problemset/leetcode-cn/originData/next-greater-element-ii.json

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            "title": "Next Greater Element II",
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            "content": "<p>Given a circular integer array <code>nums</code> (i.e., the next element of <code>nums[nums.length - 1]</code> is <code>nums[0]</code>), return <em>the <strong>next greater number</strong> for every element in</em> <code>nums</code>.</p>\n\n<p>The <strong>next greater number</strong> of a number <code>x</code> is the first greater number to its traversing-order next in the array, which means you could search circularly to find its next greater number. If it doesn&#39;t exist, return <code>-1</code> for this number.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,2,1]\n<strong>Output:</strong> [2,-1,2]\nExplanation: The first 1&#39;s next greater number is 2; \nThe number 2 can&#39;t find next greater number. \nThe second 1&#39;s next greater number needs to search circularly, which is also 2.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,2,3,4,3]\n<strong>Output:</strong> [2,3,4,-1,4]\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>4</sup></code></li>\n\t<li><code>-10<sup>9</sup> &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
            "translatedTitle": "下一个更大元素 II",
            "translatedContent": "<p>给定一个循环数组&nbsp;<code>nums</code>&nbsp;（&nbsp;<code>nums[nums.length - 1]</code>&nbsp;的下一个元素是&nbsp;<code>nums[0]</code>&nbsp;），返回&nbsp;<em><code>nums</code>&nbsp;中每个元素的 <strong>下一个更大元素</strong></em> 。</p>\n\n<p>数字 <code>x</code>&nbsp;的 <strong>下一个更大的元素</strong> 是按数组遍历顺序，这个数字之后的第一个比它更大的数，这意味着你应该循环地搜索它的下一个更大的数。如果不存在，则输出 <code>-1</code>&nbsp;。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1:</strong></p>\n\n<pre>\n<strong>输入:</strong> nums = [1,2,1]\n<strong>输出:</strong> [2,-1,2]\n<strong>解释:</strong> 第一个 1 的下一个更大的数是 2；\n数字 2 找不到下一个更大的数； \n第二个 1 的下一个最大的数需要循环搜索，结果也是 2。\n</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<pre>\n<strong>输入:</strong> nums = [1,2,3,4,3]\n<strong>输出:</strong> [2,3,4,-1,4]\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>4</sup></code></li>\n\t<li><code>-10<sup>9</sup>&nbsp;&lt;= nums[i] &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
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