mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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180 lines
21 KiB
JSON
180 lines
21 KiB
JSON
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"title": "Minimum Size Subarray Sum",
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"content": "<p>Given an array of positive integers <code>nums</code> and a positive integer <code>target</code>, return the minimal length of a <strong>contiguous subarray</strong> <code>[nums<sub>l</sub>, nums<sub>l+1</sub>, ..., nums<sub>r-1</sub>, nums<sub>r</sub>]</code> of which the sum is greater than or equal to <code>target</code>. If there is no such subarray, return <code>0</code> instead.</p>\n\n<p> </p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> target = 7, nums = [2,3,1,2,4,3]\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> The subarray [4,3] has the minimal length under the problem constraint.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> target = 4, nums = [1,4,4]\n<strong>Output:</strong> 1\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> target = 11, nums = [1,1,1,1,1,1,1,1]\n<strong>Output:</strong> 0\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= target <= 10<sup>9</sup></code></li>\n\t<li><code>1 <= nums.length <= 10<sup>5</sup></code></li>\n\t<li><code>1 <= nums[i] <= 10<sup>5</sup></code></li>\n</ul>\n\n<p> </p>\n<strong>Follow up:</strong> If you have figured out the <code>O(n)</code> solution, try coding another solution of which the time complexity is <code>O(n log(n))</code>.",
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"translatedContent": "<p>给定一个含有 <code>n</code><strong> </strong>个正整数的数组和一个正整数 <code>target</code><strong> 。</strong></p>\n\n<p>找出该数组中满足其和<strong> </strong><code>≥ target</code><strong> </strong>的长度最小的 <strong>连续子数组</strong> <code>[nums<sub>l</sub>, nums<sub>l+1</sub>, ..., nums<sub>r-1</sub>, nums<sub>r</sub>]</code> ，并返回其长度<strong>。</strong>如果不存在符合条件的子数组，返回 <code>0</code> 。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>target = 7, nums = [2,3,1,2,4,3]\n<strong>输出：</strong>2\n<strong>解释：</strong>子数组 <code>[4,3]</code> 是该条件下的长度最小的子数组。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>target = 4, nums = [1,4,4]\n<strong>输出：</strong>1\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>target = 11, nums = [1,1,1,1,1,1,1,1]\n<strong>输出：</strong>0\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 <= target <= 10<sup>9</sup></code></li>\n\t<li><code>1 <= nums.length <= 10<sup>5</sup></code></li>\n\t<li><code>1 <= nums[i] <= 10<sup>5</sup></code></li>\n</ul>\n\n<p> </p>\n\n<p><strong>进阶：</strong></p>\n\n<ul>\n\t<li>如果你已经实现<em> </em><code>O(n)</code> 时间复杂度的解法, 请尝试设计一个 <code>O(n log(n))</code> 时间复杂度的解法。</li>\n</ul>\n",
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