leetcode-problemset/leetcode-cn/originData/minimum-number-of-taps-to-open-to-water-a-garden.json

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            "questionId": "1451",
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            "categoryTitle": "Algorithms",
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            "title": "Minimum Number of Taps to Open to Water a Garden",
            "titleSlug": "minimum-number-of-taps-to-open-to-water-a-garden",
            "content": "<p>There is a one-dimensional garden on the x-axis. The garden starts at the point <code>0</code> and ends at the point <code>n</code>. (i.e The length of the garden is <code>n</code>).</p>\n\n<p>There are <code>n + 1</code> taps located at points <code>[0, 1, ..., n]</code> in the garden.</p>\n\n<p>Given an integer <code>n</code> and an integer array <code>ranges</code> of length <code>n + 1</code> where <code>ranges[i]</code> (0-indexed) means the <code>i-th</code> tap can water the area <code>[i - ranges[i], i + ranges[i]]</code> if it was open.</p>\n\n<p>Return <em>the minimum number of taps</em> that should be open to water the whole garden, If the garden cannot be watered return <strong>-1</strong>.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/01/16/1685_example_1.png\" style=\"width: 525px; height: 255px;\" />\n<pre>\n<strong>Input:</strong> n = 5, ranges = [3,4,1,1,0,0]\n<strong>Output:</strong> 1\n<strong>Explanation:</strong> The tap at point 0 can cover the interval [-3,3]\nThe tap at point 1 can cover the interval [-3,5]\nThe tap at point 2 can cover the interval [1,3]\nThe tap at point 3 can cover the interval [2,4]\nThe tap at point 4 can cover the interval [4,4]\nThe tap at point 5 can cover the interval [5,5]\nOpening Only the second tap will water the whole garden [0,5]\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 3, ranges = [0,0,0,0]\n<strong>Output:</strong> -1\n<strong>Explanation:</strong> Even if you activate all the four taps you cannot water the whole garden.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n &lt;= 10<sup>4</sup></code></li>\n\t<li><code>ranges.length == n + 1</code></li>\n\t<li><code>0 &lt;= ranges[i] &lt;= 100</code></li>\n</ul>\n",
            "translatedTitle": "灌溉花园的最少水龙头数目",
            "translatedContent": "<p>在 x 轴上有一个一维的花园。花园长度为&nbsp;<code>n</code>，从点&nbsp;<code>0</code>&nbsp;开始，到点&nbsp;<code>n</code>&nbsp;结束。</p>\n\n<p>花园里总共有&nbsp;<code>n + 1</code> 个水龙头，分别位于&nbsp;<code>[0, 1, ..., n]</code> 。</p>\n\n<p>给你一个整数&nbsp;<code>n</code>&nbsp;和一个长度为&nbsp;<code>n + 1</code> 的整数数组&nbsp;<code>ranges</code>&nbsp;，其中&nbsp;<code>ranges[i]</code> （下标从 0 开始）表示：如果打开点&nbsp;<code>i</code>&nbsp;处的水龙头，可以灌溉的区域为&nbsp;<code>[i -&nbsp; ranges[i], i + ranges[i]]</code>&nbsp;。</p>\n\n<p>请你返回可以灌溉整个花园的&nbsp;<strong>最少水龙头数目</strong>&nbsp;。如果花园始终存在无法灌溉到的地方，请你返回&nbsp;<strong>-1</strong>&nbsp;。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode-cn.com/aliyun-lc-upload/uploads/2020/01/19/1685_example_1.png\" /></p>\n\n<pre>\n<strong>输入：</strong>n = 5, ranges = [3,4,1,1,0,0]\n<strong>输出：</strong>1\n<strong>解释：\n</strong>点 0 处的水龙头可以灌溉区间 [-3,3]\n点 1 处的水龙头可以灌溉区间 [-3,5]\n点 2 处的水龙头可以灌溉区间 [1,3]\n点 3 处的水龙头可以灌溉区间 [2,4]\n点 4 处的水龙头可以灌溉区间 [4,4]\n点 5 处的水龙头可以灌溉区间 [5,5]\n只需要打开点 1 处的水龙头即可灌溉整个花园 [0,5] 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>n = 3, ranges = [0,0,0,0]\n<strong>输出：</strong>-1\n<strong>解释：</strong>即使打开所有水龙头，你也无法灌溉整个花园。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n &lt;= 10<sup>4</sup></code></li>\n\t<li><code>ranges.length == n + 1</code></li>\n\t<li><code>0 &lt;= ranges[i] &lt;= 100</code></li>\n</ul>\n",
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                "Create intervals of the area covered by each tap, sort intervals by the left end.",
                "We need to cover the interval [0, n]. we can start with the first interval and out of all intervals that intersect with it we choose the one that covers the farthest point to the right.",
                "What if there is a gap between intervals that is not covered ? we should stop and return -1 as there is some interval that cannot be covered."
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