leetcode-problemset/leetcode-cn/originData/maximum-gap.json

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            "categoryTitle": "Algorithms",
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            "title": "Maximum Gap",
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            "content": "<p>Given an integer array <code>nums</code>, return <em>the maximum difference between two successive elements in its sorted form</em>. If the array contains less than two elements, return <code>0</code>.</p>\n\n<p>You must write an algorithm that runs in linear time and uses linear extra space.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [3,6,9,1]\n<strong>Output:</strong> 3\n<strong>Explanation:</strong> The sorted form of the array is [1,3,6,9], either (3,6) or (6,9) has the maximum difference 3.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [10]\n<strong>Output:</strong> 0\n<strong>Explanation:</strong> The array contains less than 2 elements, therefore return 0.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>0 &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
            "translatedTitle": "最大间距",
            "translatedContent": "<p>给定一个无序的数组&nbsp;<code>nums</code>，返回 <em>数组在排序之后，相邻元素之间最大的差值</em> 。如果数组元素个数小于 2，则返回 <code>0</code> 。</p>\n\n<p>您必须编写一个在「线性时间」内运行并使用「线性额外空间」的算法。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例&nbsp;1:</strong></p>\n\n<pre>\n<strong>输入:</strong> nums = [3,6,9,1]\n<strong>输出:</strong> 3\n<strong>解释:</strong> 排序后的数组是 [1,3,6,9]<strong><em>, </em></strong>其中相邻元素 (3,6) 和 (6,9) 之间都存在最大差值 3。</pre>\n\n<p><strong>示例&nbsp;2:</strong></p>\n\n<pre>\n<strong>输入:</strong> nums = [10]\n<strong>输出:</strong> 0\n<strong>解释:</strong> 数组元素个数小于 2，因此返回 0。</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>0 &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
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