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{
"data": {
"question": {
"questionId": "275",
"questionFrontendId": "275",
"categoryTitle": "Algorithms",
"boundTopicId": 1791,
"title": "H-Index II",
"titleSlug": "h-index-ii",
"content": "<p>Given an array of integers <code>citations</code> where <code>citations[i]</code> is the number of citations a researcher received for their <code>i<sup>th</sup></code> paper and <code>citations</code>&nbsp;is sorted in an <strong>ascending order</strong>, return compute the researcher&#39;s <code>h</code><strong>-index</strong>.</p>\n\n<p>According to the <a href=\"https://en.wikipedia.org/wiki/H-index\" target=\"_blank\">definition of h-index on Wikipedia</a>: A scientist has an index <code>h</code> if <code>h</code> of their <code>n</code> papers have at least <code>h</code> citations each, and the other <code>n &minus; h</code> papers have no more than <code>h</code> citations each.</p>\n\n<p>If there are several possible values for <code>h</code>, the maximum one is taken as the <code>h</code><strong>-index</strong>.</p>\n\n<p>You must write an algorithm that runs in logarithmic time.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> citations = [0,1,3,5,6]\n<strong>Output:</strong> 3\n<strong>Explanation:</strong> [0,1,3,5,6] means the researcher has 5 papers in total and each of them had received 0, 1, 3, 5, 6 citations respectively.\nSince the researcher has 3 papers with at least 3 citations each and the remaining two with no more than 3 citations each, their h-index is 3.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> citations = [1,2,100]\n<strong>Output:</strong> 2\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == citations.length</code></li>\n\t<li><code>1 &lt;= n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>0 &lt;= citations[i] &lt;= 1000</code></li>\n\t<li><code>citations</code> is sorted in <strong>ascending order</strong>.</li>\n</ul>\n",
"translatedTitle": "H 指数 II",
"translatedContent": "<p>给你一个整数数组 <code>citations</code> ,其中 <code>citations[i]</code> 表示研究者的第 <code>i</code> 篇论文被引用的次数,<code>citations</code> 已经按照 <strong>升序排列 </strong>。计算并返回该研究者的 <strong><code>h</code><em> </em>指数</strong>。</p>\n\n<p><a href=\"https://baike.baidu.com/item/h-index/3991452?fr=aladdin\" target=\"_blank\">h 指数的定义</a>h 代表“高引用次数”high citations一名科研人员的 h 指数是指他(她)的 <code>n</code> 篇论文中)<strong>总共</strong>有 <code>h</code> 篇论文分别被引用了<strong>至少</strong> <code>h</code> 次。且其余的 <em><code>n - h</code> </em>篇论文每篇被引用次数 <strong>不超过 </strong><em><code>h</code> </em>次。</p>\n\n<p><strong>提示:</strong>如果 <code>h</code><em> </em>有多种可能的值,<strong><code>h</code> 指数 </strong>是其中最大的那个。</p>\n\n<p>请你设计并实现对数时间复杂度的算法解决此问题。</p>\n\n<p> </p>\n\n<p><strong>示例 1</strong></p>\n\n<pre>\n<strong>输入<code></code></strong><code>citations = [0,1,3,5,6]</code>\n<strong>输出:</strong>3 \n<strong>解释:</strong>给定数组表示研究者总共有 <code>5</code> 篇论文,每篇论文相应的被引用了 0<code>, 1, 3, 5, 6</code> 次。\n  由于研究者有 <code>3 </code>篇论文每篇<strong> 至少 </strong>被引用了 <code>3</code> 次,其余两篇论文每篇被引用<strong> 不多于</strong> <code>3</code> 次,所以她的<em> h </em>指数是 <code>3</code> 。</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>citations = [1,2,100]\n<strong>输出:</strong>2\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>n == citations.length</code></li>\n\t<li><code>1 <= n <= 10<sup>5</sup></code></li>\n\t<li><code>0 <= citations[i] <= 1000</code></li>\n\t<li><code>citations</code> 按 <strong>升序排列</strong></li>\n</ul>\n",
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"difficulty": "Medium",
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"topicTags": [
{
"name": "Array",
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"translatedName": "数组",
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{
"name": "Binary Search",
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"lang": "C++",
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"code": "class Solution {\npublic:\n int hIndex(vector<int>& citations) {\n\n }\n};",
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"lang": "Java",
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"code": "class Solution {\n public int hIndex(int[] citations) {\n\n }\n}",
"__typename": "CodeSnippetNode"
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{
"lang": "Python",
"langSlug": "python",
"code": "class Solution(object):\n def hIndex(self, citations):\n \"\"\"\n :type citations: List[int]\n :rtype: int\n \"\"\"",
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"code": "class Solution:\n def hIndex(self, citations: List[int]) -> int:",
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"code": "\n\nint hIndex(int* citations, int citationsSize){\n\n}",
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"code": "public class Solution {\n public int HIndex(int[] citations) {\n\n }\n}",
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{
"lang": "JavaScript",
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"code": "/**\n * @param {number[]} citations\n * @return {number}\n */\nvar hIndex = function(citations) {\n\n};",
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"code": "# @param {Integer[]} citations\n# @return {Integer}\ndef h_index(citations)\n\nend",
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"code": "class Solution {\n func hIndex(_ citations: [Int]) -> Int {\n\n }\n}",
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{
"lang": "Go",
"langSlug": "golang",
"code": "func hIndex(citations []int) int {\n\n}",
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"lang": "Scala",
"langSlug": "scala",
"code": "object Solution {\n def hIndex(citations: Array[Int]): Int = {\n\n }\n}",
"__typename": "CodeSnippetNode"
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{
"lang": "Kotlin",
"langSlug": "kotlin",
"code": "class Solution {\n fun hIndex(citations: IntArray): Int {\n\n }\n}",
"__typename": "CodeSnippetNode"
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"lang": "Rust",
"langSlug": "rust",
"code": "impl Solution {\n pub fn h_index(citations: Vec<i32>) -> i32 {\n\n }\n}",
"__typename": "CodeSnippetNode"
},
{
"lang": "PHP",
"langSlug": "php",
"code": "class Solution {\n\n /**\n * @param Integer[] $citations\n * @return Integer\n */\n function hIndex($citations) {\n\n }\n}",
"__typename": "CodeSnippetNode"
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{
"lang": "TypeScript",
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"code": "function hIndex(citations: number[]): number {\n\n};",
"__typename": "CodeSnippetNode"
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"lang": "Racket",
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"code": "(define/contract (h-index citations)\n (-> (listof exact-integer?) exact-integer?)\n\n )",
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"lang": "Erlang",
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"code": "-spec h_index(Citations :: [integer()]) -> integer().\nh_index(Citations) ->\n .",
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{
"lang": "Elixir",
"langSlug": "elixir",
"code": "defmodule Solution do\n @spec h_index(citations :: [integer]) :: integer\n def h_index(citations) do\n\n end\nend",
"__typename": "CodeSnippetNode"
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"stats": "{\"totalAccepted\": \"56.9K\", \"totalSubmission\": \"124.2K\", \"totalAcceptedRaw\": 56865, \"totalSubmissionRaw\": 124195, \"acRate\": \"45.8%\"}",
"hints": [
"Expected runtime complexity is in <i>O</i>(log <i>n</i>) and the input is sorted."
],
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