mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-11 02:58:13 +08:00
200 lines
22 KiB
JSON
200 lines
22 KiB
JSON
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"categoryTitle": "Algorithms",
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"boundTopicId": 570586,
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"title": "Find Kth Largest XOR Coordinate Value",
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"titleSlug": "find-kth-largest-xor-coordinate-value",
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"content": "<p>You are given a 2D <code>matrix</code> of size <code>m x n</code>, consisting of non-negative integers. You are also given an integer <code>k</code>.</p>\n\n<p>The <strong>value</strong> of coordinate <code>(a, b)</code> of the matrix is the XOR of all <code>matrix[i][j]</code> where <code>0 <= i <= a < m</code> and <code>0 <= j <= b < n</code> <strong>(0-indexed)</strong>.</p>\n\n<p>Find the <code>k<sup>th</sup></code> largest value <strong>(1-indexed)</strong> of all the coordinates of <code>matrix</code>.</p>\n\n<p> </p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> matrix = [[5,2],[1,6]], k = 1\n<strong>Output:</strong> 7\n<strong>Explanation:</strong> The value of coordinate (0,1) is 5 XOR 2 = 7, which is the largest value.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> matrix = [[5,2],[1,6]], k = 2\n<strong>Output:</strong> 5\n<strong>Explanation:</strong> The value of coordinate (0,0) is 5 = 5, which is the 2nd largest value.\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> matrix = [[5,2],[1,6]], k = 3\n<strong>Output:</strong> 4\n<strong>Explanation:</strong> The value of coordinate (1,0) is 5 XOR 1 = 4, which is the 3rd largest value.</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>m == matrix.length</code></li>\n\t<li><code>n == matrix[i].length</code></li>\n\t<li><code>1 <= m, n <= 1000</code></li>\n\t<li><code>0 <= matrix[i][j] <= 10<sup>6</sup></code></li>\n\t<li><code>1 <= k <= m * n</code></li>\n</ul>\n",
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"translatedTitle": "找出第 K 大的异或坐标值",
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"translatedContent": "<p>给你一个二维矩阵 <code>matrix</code> 和一个整数 <code>k</code> ,矩阵大小为 <code>m x n</code> 由非负整数组成。</p>\n\n<p>矩阵中坐标 <code>(a, b)</code> 的 <strong>值</strong> 可由对所有满足 <code>0 <= i <= a < m</code> 且 <code>0 <= j <= b < n</code> 的元素 <code>matrix[i][j]</code>(<strong>下标从 0 开始计数</strong>)执行异或运算得到。</p>\n\n<p>请你找出 <code>matrix</code> 的所有坐标中第 <code>k</code> 大的值(<strong><code>k</code> 的值从 1 开始计数</strong>)。</p>\n\n<p> </p>\n\n<p><strong>示例 1:</strong></p>\n\n<pre><strong>输入:</strong>matrix = [[5,2],[1,6]], k = 1\n<strong>输出:</strong>7\n<strong>解释:</strong>坐标 (0,1) 的值是 5 XOR 2 = 7 ,为最大的值。</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<pre><strong>输入:</strong>matrix = [[5,2],[1,6]], k = 2\n<strong>输出:</strong>5\n<strong>解释:</strong>坐标 (0,0) 的值是 5 = 5 ,为第 2 大的值。</pre>\n\n<p><strong>示例 3:</strong></p>\n\n<pre><strong>输入:</strong>matrix = [[5,2],[1,6]], k = 3\n<strong>输出:</strong>4\n<strong>解释:</strong>坐标 (1,0) 的值是 5 XOR 1 = 4 ,为第 3 大的值。</pre>\n\n<p><strong>示例 4:</strong></p>\n\n<pre><strong>输入:</strong>matrix = [[5,2],[1,6]], k = 4\n<strong>输出:</strong>0\n<strong>解释:</strong>坐标 (1,1) 的值是 5 XOR 2 XOR 1 XOR 6 = 0 ,为第 4 大的值。</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>m == matrix.length</code></li>\n\t<li><code>n == matrix[i].length</code></li>\n\t<li><code>1 <= m, n <= 1000</code></li>\n\t<li><code>0 <= matrix[i][j] <= 10<sup>6</sup></code></li>\n\t<li><code>1 <= k <= m * n</code></li>\n</ul>\n",
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"Use a 2D prefix sum to precalculate the xor-sum of the upper left submatrix."
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