leetcode-problemset/leetcode-cn/originData/fei-bo-na-qi-shu-lie-lcof.json

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            "questionFrontendId": "剑指 Offer 10- I",
            "categoryTitle": "LCOF",
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            "title": "斐波那契数列  LCOF",
            "titleSlug": "fei-bo-na-qi-shu-lie-lcof",
            "content": "English description is not available for the problem. Please switch to Chinese.",
            "translatedTitle": "斐波那契数列",
            "translatedContent": "<p>写一个函数，输入 <code>n</code> ，求斐波那契（Fibonacci）数列的第 <code>n</code> 项（即 <code>F(N)</code>）。斐波那契数列的定义如下：</p>\n\n<pre>\nF(0) = 0,   F(1) = 1\nF(N) = F(N - 1) + F(N - 2), 其中 N > 1.</pre>\n\n<p>斐波那契数列由 0 和 1 开始，之后的斐波那契数就是由之前的两数相加而得出。</p>\n\n<p>答案需要取模 1e9+7（1000000007），如计算初始结果为：1000000008，请返回 1。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>n = 2\n<strong>输出：</strong>1\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>n = 5\n<strong>输出：</strong>5\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>0 <= n <= 100</code></li>\n</ul>\n",
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