mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-11 02:58:13 +08:00
125 lines
16 KiB
JSON
125 lines
16 KiB
JSON
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"categoryTitle": "LCOF",
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"boundTopicId": 88793,
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"title": "二叉搜索树的最近公共祖先 LCOF",
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"titleSlug": "er-cha-sou-suo-shu-de-zui-jin-gong-gong-zu-xian-lcof",
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"content": "<p>English description is not available for the problem. Please switch to Chinese.</p>\r\n",
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"translatedTitle": "二叉搜索树的最近公共祖先",
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"translatedContent": "<p>给定一个二叉搜索树, 找到该树中两个指定节点的最近公共祖先。</p>\n\n<p><a href=\"https://baike.baidu.com/item/%E6%9C%80%E8%BF%91%E5%85%AC%E5%85%B1%E7%A5%96%E5%85%88/8918834?fr=aladdin\" target=\"_blank\">百度百科</a>中最近公共祖先的定义为：“对于有根树 T 的两个结点 p、q，最近公共祖先表示为一个结点 x，满足 x 是 p、q 的祖先且 x 的深度尽可能大（<strong>一个节点也可以是它自己的祖先</strong>）。”</p>\n\n<p>例如，给定如下二叉搜索树: root = [6,2,8,0,4,7,9,null,null,3,5]</p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode-cn.com/aliyun-lc-upload/uploads/2018/12/14/binarysearchtree_improved.png\"></p>\n\n<p> </p>\n\n<p><strong>示例 1:</strong></p>\n\n<pre><strong>输入:</strong> root = [6,2,8,0,4,7,9,null,null,3,5], p = 2, q = 8\n<strong>输出:</strong> 6 \n<strong>解释: </strong>节点 <code>2 </code>和节点 <code>8 </code>的最近公共祖先是 <code>6。</code>\n</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<pre><strong>输入:</strong> root = [6,2,8,0,4,7,9,null,null,3,5], p = 2, q = 4\n<strong>输出:</strong> 2\n<strong>解释: </strong>节点 <code>2</code> 和节点 <code>4</code> 的最近公共祖先是 <code>2</code>, 因为根据定义最近公共祖先节点可以为节点本身。</pre>\n\n<p> </p>\n\n<p><strong>说明:</strong></p>\n\n<ul>\n\t<li>所有节点的值都是唯一的。</li>\n\t<li>p、q 为不同节点且均存在于给定的二叉搜索树中。</li>\n</ul>\n\n<p>注意：本题与主站 235 题相同：<a href=\"https://leetcode-cn.com/problems/lowest-common-ancestor-of-a-binary-search-tree/\">https://leetcode-cn.com/problems/lowest-common-ancestor-of-a-binary-search-tree/</a></p>\n",
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"name": "Binary Search Tree",
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