mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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180 lines
21 KiB
JSON
180 lines
21 KiB
JSON
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"title": "Continuous Subarray Sum",
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"content": "<p>Given an integer array <code>nums</code> and an integer <code>k</code>, return <code>true</code> <em>if </em><code>nums</code><em> has a continuous subarray of size <strong>at least two</strong> whose elements sum up to a multiple of</em> <code>k</code><em>, or </em><code>false</code><em> otherwise</em>.</p>\n\n<p>An integer <code>x</code> is a multiple of <code>k</code> if there exists an integer <code>n</code> such that <code>x = n * k</code>. <code>0</code> is <strong>always</strong> a multiple of <code>k</code>.</p>\n\n<p> </p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [23,<u>2,4</u>,6,7], k = 6\n<strong>Output:</strong> true\n<strong>Explanation:</strong> [2, 4] is a continuous subarray of size 2 whose elements sum up to 6.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [<u>23,2,6,4,7</u>], k = 6\n<strong>Output:</strong> true\n<strong>Explanation:</strong> [23, 2, 6, 4, 7] is an continuous subarray of size 5 whose elements sum up to 42.\n42 is a multiple of 6 because 42 = 7 * 6 and 7 is an integer.\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [23,2,6,4,7], k = 13\n<strong>Output:</strong> false\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= nums.length <= 10<sup>5</sup></code></li>\n\t<li><code>0 <= nums[i] <= 10<sup>9</sup></code></li>\n\t<li><code>0 <= sum(nums[i]) <= 2<sup>31</sup> - 1</code></li>\n\t<li><code>1 <= k <= 2<sup>31</sup> - 1</code></li>\n</ul>\n",
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"translatedTitle": "连续的子数组和",
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"translatedContent": "<p>给你一个整数数组 <code>nums</code> 和一个整数 <code>k</code> ，编写一个函数来判断该数组是否含有同时满足下述条件的连续子数组：</p>\n\n<ul>\n\t<li>子数组大小 <strong>至少为 2</strong> ，且</li>\n\t<li>子数组元素总和为 <code>k</code> 的倍数。</li>\n</ul>\n\n<p>如果存在，返回 <code>true</code> ；否则，返回 <code>false</code> 。</p>\n\n<p>如果存在一个整数 <code>n</code> ，令整数 <code>x</code> 符合 <code>x = n * k</code> ，则称 <code>x</code> 是 <code>k</code> 的一个倍数。<code>0</code> 始终视为 <code>k</code> 的一个倍数。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [23<u>,2,4</u>,6,7], k = 6\n<strong>输出：</strong>true\n<strong>解释：</strong>[2,4] 是一个大小为 2 的子数组，并且和为 6 。</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [<u>23,2,6,4,7</u>], k = 6\n<strong>输出：</strong>true\n<strong>解释：</strong>[23, 2, 6, 4, 7] 是大小为 5 的子数组，并且和为 42 。 \n42 是 6 的倍数，因为 42 = 7 * 6 且 7 是一个整数。\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [23,2,6,4,7], k = 13\n<strong>输出：</strong>false\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 <= nums.length <= 10<sup>5</sup></code></li>\n\t<li><code>0 <= nums[i] <= 10<sup>9</sup></code></li>\n\t<li><code>0 <= sum(nums[i]) <= 2<sup>31</sup> - 1</code></li>\n\t<li><code>1 <= k <= 2<sup>31</sup> - 1</code></li>\n</ul>\n",
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