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leetcode-problemset/leetcode-cn/originData/cong-shang-dao-xia-da-yin-er-cha-shu-ii-lcof.json
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{
"data": {
"question": {
"questionId": "100312",
"questionFrontendId": "剑指 Offer 32 - II",
"categoryTitle": "LCOF",
"boundTopicId": 87210,
"title": "从上到下打印二叉树 II LCOF",
"titleSlug": "cong-shang-dao-xia-da-yin-er-cha-shu-ii-lcof",
"content": "English description is not available for the problem. Please switch to Chinese.",
"translatedTitle": "从上到下打印二叉树 II",
"translatedContent": "<p>从上到下按层打印二叉树,同一层的节点按从左到右的顺序打印,每一层打印到一行。</p>\n\n<p>&nbsp;</p>\n\n<p>例如:<br>\n给定二叉树:&nbsp;<code>[3,9,20,null,null,15,7]</code>,</p>\n\n<pre> 3\n / \\\n 9 20\n / \\\n 15 7\n</pre>\n\n<p>返回其层次遍历结果:</p>\n\n<pre>[\n [3],\n [9,20],\n [15,7]\n]\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ol>\n\t<li><code>节点总数 &lt;= 1000</code></li>\n</ol>\n\n<p>注意:本题与主站 102 题相同:<a href=\"https://leetcode-cn.com/problems/binary-tree-level-order-traversal/\">https://leetcode-cn.com/problems/binary-tree-level-order-traversal/</a></p>\n",
"isPaidOnly": false,
"difficulty": "Easy",
"likes": 218,
"dislikes": 0,
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"similarQuestions": "[]",
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"name": "Tree",
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"translatedName": "树",
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{
"name": "Breadth-First Search",
"slug": "breadth-first-search",
"translatedName": "广度优先搜索",
"__typename": "TopicTagNode"
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{
"name": "Binary Tree",
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"translatedName": "二叉树",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * int val;\n * TreeNode left;\n * TreeNode right;\n * TreeNode(int x) { val = x; }\n * }\n */\nclass Solution {\n public List<List<Integer>> levelOrder(TreeNode root) {\n\n }\n}",
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"code": "# Definition for a binary tree node.\n# class TreeNode(object):\n# def __init__(self, x):\n# self.val = x\n# self.left = None\n# self.right = None\n\nclass Solution(object):\n def levelOrder(self, root):\n \"\"\"\n :type root: TreeNode\n :rtype: List[List[int]]\n \"\"\"",
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"code": "# Definition for a binary tree node.\n# class TreeNode:\n# def __init__(self, x):\n# self.val = x\n# self.left = None\n# self.right = None\n\nclass Solution:\n def levelOrder(self, root: TreeNode) -> List[List[int]]:",
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"code": "/**\n * Definition for a binary tree node.\n * struct TreeNode {\n * int val;\n * struct TreeNode *left;\n * struct TreeNode *right;\n * };\n */\n\n\n/**\n * Return an array of arrays of size *returnSize.\n * The sizes of the arrays are returned as *returnColumnSizes array.\n * Note: Both returned array and *columnSizes array must be malloced, assume caller calls free().\n */\nint** levelOrder(struct TreeNode* root, int* returnSize, int** returnColumnSizes){\n\n}\n",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public int val;\n * public TreeNode left;\n * public TreeNode right;\n * public TreeNode(int x) { val = x; }\n * }\n */\npublic class Solution {\n public IList<IList<int>> LevelOrder(TreeNode root) {\n\n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * function TreeNode(val) {\n * this.val = val;\n * this.left = this.right = null;\n * }\n */\n/**\n * @param {TreeNode} root\n * @return {number[][]}\n */\nvar levelOrder = function(root) {\n\n};",
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"code": "# Definition for a binary tree node.\n# class TreeNode\n# attr_accessor :val, :left, :right\n# def initialize(val)\n# @val = val\n# @left, @right = nil, nil\n# end\n# end\n\n# @param {TreeNode} root\n# @return {Integer[][]}\ndef level_order(root)\n\nend",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public var val: Int\n * public var left: TreeNode?\n * public var right: TreeNode?\n * public init(_ val: Int) {\n * self.val = val\n * self.left = nil\n * self.right = nil\n * }\n * }\n */\nclass Solution {\n func levelOrder(_ root: TreeNode?) -> [[Int]] {\n\n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * type TreeNode struct {\n * Val int\n * Left *TreeNode\n * Right *TreeNode\n * }\n */\nfunc levelOrder(root *TreeNode) [][]int {\n\n}",
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"lang": "Kotlin",
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"code": "/**\n * Example:\n * var ti = TreeNode(5)\n * var v = ti.`val`\n * Definition for a binary tree node.\n * class TreeNode(var `val`: Int) {\n * var left: TreeNode? = null\n * var right: TreeNode? = null\n * }\n */\nclass Solution {\n fun levelOrder(root: TreeNode?): List<List<Int>> {\n\n }\n}",
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"code": "// Definition for a binary tree node.\n// #[derive(Debug, PartialEq, Eq)]\n// pub struct TreeNode {\n// pub val: i32,\n// pub left: Option<Rc<RefCell<TreeNode>>>,\n// pub right: Option<Rc<RefCell<TreeNode>>>,\n// }\n// \n// impl TreeNode {\n// #[inline]\n// pub fn new(val: i32) -> Self {\n// TreeNode {\n// val,\n// left: None,\n// right: None\n// }\n// }\n// }\nuse std::rc::Rc;\nuse std::cell::RefCell;\nimpl Solution {\n pub fn level_order(root: Option<Rc<RefCell<TreeNode>>>) -> Vec<Vec<i32>> {\n\n }\n}",
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"code": "; Definition for a binary tree node.\n#|\n\n; val : integer?\n; left : (or/c tree-node? #f)\n; right : (or/c tree-node? #f)\n(struct tree-node\n (val left right) #:mutable #:transparent)\n\n; constructor\n(define (make-tree-node [val 0])\n (tree-node val #f #f))\n\n|#\n\n(define/contract (level-order root)\n (-> (or/c tree-node? #f) (listof (listof exact-integer?)))\n\n )",
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