mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-11 02:58:13 +08:00
182 lines
19 KiB
JSON
182 lines
19 KiB
JSON
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"questionId": "100161",
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"questionFrontendId": "面试题 01.06",
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"categoryTitle": "LCCI",
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"boundTopicId": 45552,
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"title": "Compress String LCCI",
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"content": "<p>Implement a method to perform basic string compression using the counts of repeated characters. For example, the string aabcccccaaa would become a2blc5a3. If the "compressed" string would not become smaller than the original string, your method should return the original string. You can assume the string has only uppercase and lowercase letters (a - z).</p>\r\n\r\n<p><strong>Example 1:</strong></p>\r\n\r\n<pre>\r\n<strong>Input: </strong>"aabcccccaaa"\r\n<strong>Output: </strong>"a2b1c5a3"\r\n</pre>\r\n\r\n<p><strong>Example 2:</strong></p>\r\n\r\n<pre>\r\n<strong>Input: </strong>"abbccd"\r\n<strong>Output: </strong>"abbccd"\r\n<strong>Explanation: </strong>\r\nThe compressed string is "a1b2c2d1", which is longer than the original string.\r\n</pre>\r\n\r\n<p> </p>\r\n\r\n<p><strong>Note:</strong></p>\r\n\r\n<ol>\r\n\t<li><code>0 <= S.length <= 50000</code></li>\r\n</ol>\r\n",
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"translatedTitle": "字符串压缩",
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"translatedContent": "<p>字符串压缩。利用字符重复出现的次数，编写一种方法，实现基本的字符串压缩功能。比如，字符串<code>aabcccccaaa</code>会变为<code>a2b1c5a3</code>。若“压缩”后的字符串没有变短，则返回原先的字符串。你可以假设字符串中只包含大小写英文字母（a至z）。</p>\n\n<p> <strong>示例1:</strong></p>\n\n<pre>\n<strong> 输入</strong>：\"aabcccccaaa\"\n<strong> 输出</strong>：\"a2b1c5a3\"\n</pre>\n\n<p> <strong>示例2:</strong></p>\n\n<pre>\n<strong> 输入</strong>：\"abbccd\"\n<strong> 输出</strong>：\"abbccd\"\n<strong> 解释</strong>：\"abbccd\"压缩后为\"a1b2c2d1\"，比原字符串长度更长。\n</pre>\n\n<p><strong>提示：</strong></p>\n\n<ol>\n<li>字符串长度在[0, 50000]范围内。</li>\n</ol>\n",
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"hints": [
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"先做容易的事。压缩字符串，然后再比较长度。",
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"注意不要把字符串重复连接在一起。这会非常低效。"
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