mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-11 02:58:13 +08:00
195 lines
30 KiB
JSON
195 lines
30 KiB
JSON
{
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"data": {
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"question": {
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"questionId": "2567",
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"questionFrontendId": "2476",
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"categoryTitle": "Algorithms",
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"boundTopicId": 1974250,
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"title": "Closest Nodes Queries in a Binary Search Tree",
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"titleSlug": "closest-nodes-queries-in-a-binary-search-tree",
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"content": "<p>You are given the <code>root</code> of a <strong>binary search tree </strong>and an array <code>queries</code> of size <code>n</code> consisting of positive integers.</p>\n\n<p>Find a <strong>2D</strong> array <code>answer</code> of size <code>n</code> where <code>answer[i] = [min<sub>i</sub>, max<sub>i</sub>]</code>:</p>\n\n<ul>\n\t<li><code>min<sub>i</sub></code> is the <strong>largest</strong> value in the tree that is smaller than or equal to <code>queries[i]</code>. If a such value does not exist, add <code>-1</code> instead.</li>\n\t<li><code>max<sub>i</sub></code> is the <strong>smallest</strong> value in the tree that is greater than or equal to <code>queries[i]</code>. If a such value does not exist, add <code>-1</code> instead.</li>\n</ul>\n\n<p>Return <em>the array</em> <code>answer</code>.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2022/09/28/bstreeedrawioo.png\" style=\"width: 261px; height: 281px;\" />\n<pre>\n<strong>Input:</strong> root = [6,2,13,1,4,9,15,null,null,null,null,null,null,14], queries = [2,5,16]\n<strong>Output:</strong> [[2,2],[4,6],[15,-1]]\n<strong>Explanation:</strong> We answer the queries in the following way:\n- The largest number that is smaller or equal than 2 in the tree is 2, and the smallest number that is greater or equal than 2 is still 2. So the answer for the first query is [2,2].\n- The largest number that is smaller or equal than 5 in the tree is 4, and the smallest number that is greater or equal than 5 is 6. So the answer for the second query is [4,6].\n- The largest number that is smaller or equal than 16 in the tree is 15, and the smallest number that is greater or equal than 16 does not exist. So the answer for the third query is [15,-1].\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2022/09/28/bstttreee.png\" style=\"width: 101px; height: 121px;\" />\n<pre>\n<strong>Input:</strong> root = [4,null,9], queries = [3]\n<strong>Output:</strong> [[-1,4]]\n<strong>Explanation:</strong> The largest number that is smaller or equal to 3 in the tree does not exist, and the smallest number that is greater or equal to 3 is 4. So the answer for the query is [-1,4].\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li>The number of nodes in the tree is in the range <code>[2, 10<sup>5</sup>]</code>.</li>\n\t<li><code>1 <= Node.val <= 10<sup>6</sup></code></li>\n\t<li><code>n == queries.length</code></li>\n\t<li><code>1 <= n <= 10<sup>5</sup></code></li>\n\t<li><code>1 <= queries[i] <= 10<sup>6</sup></code></li>\n</ul>\n",
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"translatedTitle": "二叉搜索树最近节点查询",
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"translatedContent": "<p>给你一个 <strong>二叉搜索树</strong> 的根节点 <code>root</code> ,和一个由正整数组成、长度为 <code>n</code> 的数组 <code>queries</code> 。</p>\n\n<p>请你找出一个长度为 <code>n</code> 的 <strong>二维</strong> 答案数组 <code>answer</code> ,其中 <code>answer[i] = [min<sub>i</sub>, max<sub>i</sub>]</code> :</p>\n\n<ul>\n\t<li><code>min<sub>i</sub></code> 是树中小于等于 <code>queries[i]</code> 的 <strong>最大值</strong> 。如果不存在这样的值,则使用 <code>-1</code> 代替。</li>\n\t<li><code>max<sub>i</sub></code> 是树中大于等于 <code>queries[i]</code> 的 <strong>最小值</strong> 。如果不存在这样的值,则使用 <code>-1</code> 代替。</li>\n</ul>\n\n<p>返回数组 <code>answer</code> 。</p>\n\n<p> </p>\n\n<p><strong>示例 1 :</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2022/09/28/bstreeedrawioo.png\" style=\"width: 261px; height: 281px;\" /></p>\n\n<pre>\n<strong>输入:</strong>root = [6,2,13,1,4,9,15,null,null,null,null,null,null,14], queries = [2,5,16]\n<strong>输出:</strong>[[2,2],[4,6],[15,-1]]\n<strong>解释:</strong>按下面的描述找出并返回查询的答案:\n- 树中小于等于 2 的最大值是 2 ,且大于等于 2 的最小值也是 2 。所以第一个查询的答案是 [2,2] 。\n- 树中小于等于 5 的最大值是 4 ,且大于等于 5 的最小值是 6 。所以第二个查询的答案是 [4,6] 。\n- 树中小于等于 16 的最大值是 15 ,且大于等于 16 的最小值不存在。所以第三个查询的答案是 [15,-1] 。\n</pre>\n\n<p><strong>示例 2 :</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2022/09/28/bstttreee.png\" style=\"width: 101px; height: 121px;\" /></p>\n\n<pre>\n<strong>输入:</strong>root = [4,null,9], queries = [3]\n<strong>输出:</strong>[[-1,4]]\n<strong>解释:</strong>树中不存在小于等于 3 的最大值,且大于等于 3 的最小值是 4 。所以查询的答案是 [-1,4] 。\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li>树中节点的数目在范围 <code>[2, 10<sup>5</sup>]</code> 内</li>\n\t<li><code>1 <= Node.val <= 10<sup>6</sup></code></li>\n\t<li><code>n == queries.length</code></li>\n\t<li><code>1 <= n <= 10<sup>5</sup></code></li>\n\t<li><code>1 <= queries[i] <= 10<sup>6</sup></code></li>\n</ul>\n",
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"code": "/**\n * Definition for a binary tree node.\n * struct TreeNode {\n * int val;\n * TreeNode *left;\n * TreeNode *right;\n * TreeNode() : val(0), left(nullptr), right(nullptr) {}\n * TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}\n * TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}\n * };\n */\nclass Solution {\npublic:\n vector<vector<int>> closestNodes(TreeNode* root, vector<int>& queries) {\n \n }\n};",
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"code": "/**\n * Definition for a binary tree node.\n * struct TreeNode {\n * int val;\n * struct TreeNode *left;\n * struct TreeNode *right;\n * };\n */\n/**\n * Return an array of arrays of size *returnSize.\n * The sizes of the arrays are returned as *returnColumnSizes array.\n * Note: Both returned array and *columnSizes array must be malloced, assume caller calls free().\n */\nint** closestNodes(struct TreeNode* root, int* queries, int queriesSize, int* returnSize, int** returnColumnSizes){\n\n}",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public int val;\n * public TreeNode left;\n * public TreeNode right;\n * public TreeNode(int val=0, TreeNode left=null, TreeNode right=null) {\n * this.val = val;\n * this.left = left;\n * this.right = right;\n * }\n * }\n */\npublic class Solution {\n public IList<IList<int>> ClosestNodes(TreeNode root, IList<int> queries) {\n\n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * function TreeNode(val, left, right) {\n * this.val = (val===undefined ? 0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n */\n/**\n * @param {TreeNode} root\n * @param {number[]} queries\n * @return {number[][]}\n */\nvar closestNodes = function(root, queries) {\n\n};",
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"code": "# Definition for a binary tree node.\n# class TreeNode\n# attr_accessor :val, :left, :right\n# def initialize(val = 0, left = nil, right = nil)\n# @val = val\n# @left = left\n# @right = right\n# end\n# end\n# @param {TreeNode} root\n# @param {Integer[]} queries\n# @return {Integer[][]}\ndef closest_nodes(root, queries)\n\nend",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public var val: Int\n * public var left: TreeNode?\n * public var right: TreeNode?\n * public init() { self.val = 0; self.left = nil; self.right = nil; }\n * public init(_ val: Int) { self.val = val; self.left = nil; self.right = nil; }\n * public init(_ val: Int, _ left: TreeNode?, _ right: TreeNode?) {\n * self.val = val\n * self.left = left\n * self.right = right\n * }\n * }\n */\nclass Solution {\n func closestNodes(_ root: TreeNode?, _ queries: [Int]) -> [[Int]] {\n\n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * type TreeNode struct {\n * Val int\n * Left *TreeNode\n * Right *TreeNode\n * }\n */\nfunc closestNodes(root *TreeNode, queries []int) [][]int {\n\n}",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode(_value: Int = 0, _left: TreeNode = null, _right: TreeNode = null) {\n * var value: Int = _value\n * var left: TreeNode = _left\n * var right: TreeNode = _right\n * }\n */\nobject Solution {\n def closestNodes(root: TreeNode, queries: List[Int]): List[List[Int]] = {\n\n }\n}",
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"code": "// Definition for a binary tree node.\n// #[derive(Debug, PartialEq, Eq)]\n// pub struct TreeNode {\n// pub val: i32,\n// pub left: Option<Rc<RefCell<TreeNode>>>,\n// pub right: Option<Rc<RefCell<TreeNode>>>,\n// }\n//\n// impl TreeNode {\n// #[inline]\n// pub fn new(val: i32) -> Self {\n// TreeNode {\n// val,\n// left: None,\n// right: None\n// }\n// }\n// }\nuse std::rc::Rc;\nuse std::cell::RefCell;\nimpl Solution {\n pub fn closest_nodes(root: Option<Rc<RefCell<TreeNode>>>, queries: Vec<i32>) -> Vec<Vec<i32>> {\n\n }\n}",
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