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54 lines
3.2 KiB
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54 lines
3.2 KiB
HTML
<p>输入两个链表,找出它们的第一个公共节点。</p>
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<p>如下面的两个链表<strong>:</strong></p>
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<p><a href="https://assets.leetcode-cn.com/aliyun-lc-upload/uploads/2018/12/14/160_statement.png" target="_blank"><img alt="" src="https://assets.leetcode-cn.com/aliyun-lc-upload/uploads/2018/12/14/160_statement.png" style="height: 130px; width: 400px;"></a></p>
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<p>在节点 c1 开始相交。</p>
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<p> </p>
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<p><strong>示例 1:</strong></p>
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<p><a href="https://assets.leetcode.com/uploads/2018/12/13/160_example_1.png" target="_blank"><img alt="" src="https://assets.leetcode-cn.com/aliyun-lc-upload/uploads/2018/12/14/160_example_1.png" style="height: 130px; width: 400px;"></a></p>
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<pre><strong>输入:</strong>intersectVal = 8, listA = [4,1,8,4,5], listB = [5,0,1,8,4,5], skipA = 2, skipB = 3
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<strong>输出:</strong>Reference of the node with value = 8
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<strong>输入解释:</strong>相交节点的值为 8 (注意,如果两个列表相交则不能为 0)。从各自的表头开始算起,链表 A 为 [4,1,8,4,5],链表 B 为 [5,0,1,8,4,5]。在 A 中,相交节点前有 2 个节点;在 B 中,相交节点前有 3 个节点。
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</pre>
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<p> </p>
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<p><strong>示例 2:</strong></p>
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<p><a href="https://assets.leetcode.com/uploads/2018/12/13/160_example_2.png" target="_blank"><img alt="" src="https://assets.leetcode-cn.com/aliyun-lc-upload/uploads/2018/12/14/160_example_2.png" style="height: 136px; width: 350px;"></a></p>
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<pre><strong>输入:</strong>intersectVal = 2, listA = [0,9,1,2,4], listB = [3,2,4], skipA = 3, skipB = 1
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<strong>输出:</strong>Reference of the node with value = 2
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<strong>输入解释:</strong>相交节点的值为 2 (注意,如果两个列表相交则不能为 0)。从各自的表头开始算起,链表 A 为 [0,9,1,2,4],链表 B 为 [3,2,4]。在 A 中,相交节点前有 3 个节点;在 B 中,相交节点前有 1 个节点。
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</pre>
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<p> </p>
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<p><strong>示例 3:</strong></p>
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<p><a href="https://assets.leetcode.com/uploads/2018/12/13/160_example_3.png" target="_blank"><img alt="" src="https://assets.leetcode-cn.com/aliyun-lc-upload/uploads/2018/12/14/160_example_3.png" style="height: 126px; width: 200px;"></a></p>
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<pre><strong>输入:</strong>intersectVal = 0, listA = [2,6,4], listB = [1,5], skipA = 3, skipB = 2
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<strong>输出:</strong>null
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<strong>输入解释:</strong>从各自的表头开始算起,链表 A 为 [2,6,4],链表 B 为 [1,5]。由于这两个链表不相交,所以 intersectVal 必须为 0,而 skipA 和 skipB 可以是任意值。
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<strong>解释:</strong>这两个链表不相交,因此返回 null。
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</pre>
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<p> </p>
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<p><strong>注意:</strong></p>
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<ul>
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<li>如果两个链表没有交点,返回 <code>null</code>.</li>
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<li>在返回结果后,两个链表仍须保持原有的结构。</li>
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<li>可假定整个链表结构中没有循环。</li>
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<li>程序尽量满足 O(<em>n</em>) 时间复杂度,且仅用 O(<em>1</em>) 内存。</li>
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<li>本题与主站 160 题相同:<a href="https://leetcode-cn.com/problems/intersection-of-two-linked-lists/">https://leetcode-cn.com/problems/intersection-of-two-linked-lists/</a></li>
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</ul>
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