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"questionFrontendId": "LCP 13",
"categoryTitle": "Algorithms",
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"title": "寻宝",
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"translatedContent": "<p>我们得到了一副藏宝图,藏宝图显示,在一个迷宫中存在着未被世人发现的宝藏。</p>\n\n<p>迷宫是一个二维矩阵,用一个字符串数组表示。它标识了唯一的入口(用 &#39;S&#39; 表示),和唯一的宝藏地点(用 &#39;T&#39; 表示)。但是,宝藏被一些隐蔽的机关保护了起来。在地图上有若干个机关点(用 &#39;M&#39; 表示),<strong>只有所有机关均被触发,才可以拿到宝藏。</strong></p>\n\n<p>要保持机关的触发,需要把一个重石放在上面。迷宫中有若干个石堆(用 &#39;O&#39; 表示),每个石堆都有<strong>无限</strong>个足够触发机关的重石。但是由于石头太重,我们一次只能搬<strong>一个</strong>石头到指定地点。</p>\n\n<p>迷宫中同样有一些墙壁(用 &#39;#&#39; 表示),我们不能走入墙壁。剩余的都是可随意通行的点(用 &#39;.&#39; 表示)。石堆、机关、起点和终点(无论是否能拿到宝藏)也是可以通行的。</p>\n\n<p>我们每步可以选择向上/向下/向左/向右移动一格,并且不能移出迷宫。搬起石头和放下石头不算步数。那么,从起点开始,我们最少需要多少步才能最后拿到宝藏呢?如果无法拿到宝藏,返回 -1 。</p>\n\n<p><strong>示例 1</strong></p>\n\n<blockquote>\n<p>输入: [&quot;S#O&quot;, &quot;M..&quot;, &quot;M.T&quot;]</p>\n\n<p>输出16</p>\n\n<p>解释:最优路线为: S-&gt;O, cost = 4, 去搬石头 O-&gt;第二行的M, cost = 3, M机关触发 第二行的M-&gt;O, cost = 3, 我们需要继续回去 O 搬石头。 O-&gt;第三行的M, cost = 4, 此时所有机关均触发 第三行的M-&gt;T, cost = 2去T点拿宝藏。 总步数为16。 <img alt=\"图片.gif\" src=\"https://pic.leetcode-cn.com/6bfff669ad65d494cdc237bcedfec10a2b1ac2f2593c2bf97e9aecb41dc8a08b-%E5%9B%BE%E7%89%87.gif\" /></p>\n</blockquote>\n\n<p><strong>示例 2</strong></p>\n\n<blockquote>\n<p>输入: [&quot;S#O&quot;, &quot;M.#&quot;, &quot;M.T&quot;]</p>\n\n<p>输出:-1</p>\n\n<p>解释:我们无法搬到石头触发机关</p>\n</blockquote>\n\n<p><strong>示例 3</strong></p>\n\n<blockquote>\n<p>输入: [&quot;S#O&quot;, &quot;M.T&quot;, &quot;M..&quot;]</p>\n\n<p>输出17</p>\n\n<p>解释:注意终点也是可以通行的。</p>\n</blockquote>\n\n<p><strong>限制:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= maze.length&nbsp;&lt;= 100</code></li>\n\t<li><code>1 &lt;= maze[i].length&nbsp;&lt;= 100</code></li>\n\t<li><code>maze[i].length == maze[j].length</code></li>\n\t<li>S 和 T 有且只有一个</li>\n\t<li>0 &lt;= M的数量 &lt;= 16</li>\n\t<li>0 &lt;= O的数量 &lt;= 40题目保证当迷宫中存在 M 时,一定存在至少一个 O 。</li>\n</ul>\n",
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