leetcode-problemset/leetcode-cn/originData/split-two-strings-to-make-palindrome.json

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            "questionId": "1739",
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            "categoryTitle": "Algorithms",
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            "title": "Split Two Strings to Make Palindrome",
            "titleSlug": "split-two-strings-to-make-palindrome",
            "content": "<p>You are given two strings <code>a</code> and <code>b</code> of the same length. Choose an index and split both strings <strong>at the same index</strong>, splitting <code>a</code> into two strings: <code>a<sub>prefix</sub></code> and <code>a<sub>suffix</sub></code> where <code>a = a<sub>prefix</sub> + a<sub>suffix</sub></code>, and splitting <code>b</code> into two strings: <code>b<sub>prefix</sub></code> and <code>b<sub>suffix</sub></code> where <code>b = b<sub>prefix</sub> + b<sub>suffix</sub></code>. Check if <code>a<sub>prefix</sub> + b<sub>suffix</sub></code> or <code>b<sub>prefix</sub> + a<sub>suffix</sub></code> forms a palindrome.</p>\n\n<p>When you split a string <code>s</code> into <code>s<sub>prefix</sub></code> and <code>s<sub>suffix</sub></code>, either <code>s<sub>suffix</sub></code> or <code>s<sub>prefix</sub></code> is allowed to be empty. For example, if <code>s = &quot;abc&quot;</code>, then <code>&quot;&quot; + &quot;abc&quot;</code>, <code>&quot;a&quot; + &quot;bc&quot;</code>, <code>&quot;ab&quot; + &quot;c&quot;</code> , and <code>&quot;abc&quot; + &quot;&quot;</code> are valid splits.</p>\n\n<p>Return <code>true</code><em> if it is possible to form</em><em> a palindrome string, otherwise return </em><code>false</code>.</p>\n\n<p><strong>Notice</strong> that&nbsp;<code>x + y</code> denotes the concatenation of strings <code>x</code> and <code>y</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> a = &quot;x&quot;, b = &quot;y&quot;\n<strong>Output:</strong> true\n<strong>Explaination:</strong> If either a or b are palindromes the answer is true since you can split in the following way:\na<sub>prefix</sub> = &quot;&quot;, a<sub>suffix</sub> = &quot;x&quot;\nb<sub>prefix</sub> = &quot;&quot;, b<sub>suffix</sub> = &quot;y&quot;\nThen, a<sub>prefix</sub> + b<sub>suffix</sub> = &quot;&quot; + &quot;y&quot; = &quot;y&quot;, which is a palindrome.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> a = &quot;xbdef&quot;, b = &quot;xecab&quot;\n<strong>Output:</strong> false\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> a = &quot;ulacfd&quot;, b = &quot;jizalu&quot;\n<strong>Output:</strong> true\n<strong>Explaination:</strong> Split them at index 3:\na<sub>prefix</sub> = &quot;ula&quot;, a<sub>suffix</sub> = &quot;cfd&quot;\nb<sub>prefix</sub> = &quot;jiz&quot;, b<sub>suffix</sub> = &quot;alu&quot;\nThen, a<sub>prefix</sub> + b<sub>suffix</sub> = &quot;ula&quot; + &quot;alu&quot; = &quot;ulaalu&quot;, which is a palindrome.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= a.length, b.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>a.length == b.length</code></li>\n\t<li><code>a</code> and <code>b</code> consist of lowercase English letters</li>\n</ul>\n",
            "translatedTitle": "分割两个字符串得到回文串",
            "translatedContent": "<p>给你两个字符串&nbsp;<code>a</code> 和&nbsp;<code>b</code>&nbsp;，它们长度相同。请你选择一个下标，将两个字符串都在&nbsp;<strong>相同的下标 </strong>分割开。由&nbsp;<code>a</code>&nbsp;可以得到两个字符串：&nbsp;<code>a<sub>prefix</sub></code>&nbsp;和&nbsp;<code>a<sub>suffix</sub></code>&nbsp;，满足&nbsp;<code>a = a<sub>prefix</sub> + a<sub>suffix</sub></code><sub>&nbsp;</sub>，同理，由&nbsp;<code>b</code> 可以得到两个字符串&nbsp;<code>b<sub>prefix</sub></code> 和&nbsp;<code>b<sub>suffix</sub></code>&nbsp;，满足&nbsp;<code>b = b<sub>prefix</sub> + b<sub>suffix</sub></code>&nbsp;。请你判断&nbsp;<code>a<sub>prefix</sub> + b<sub>suffix</sub></code> 或者&nbsp;<code>b<sub>prefix</sub> + a<sub>suffix</sub></code>&nbsp;能否构成回文串。</p>\n\n<p>当你将一个字符串&nbsp;<code>s</code>&nbsp;分割成&nbsp;<code>s<sub>prefix</sub></code> 和&nbsp;<code>s<sub>suffix</sub></code>&nbsp;时，&nbsp;<code>s<sub>suffix</sub></code> 或者&nbsp;<code>s<sub>prefix</sub></code> 可以为空。比方说，&nbsp;<code>s = \"abc\"</code>&nbsp;那么&nbsp;<code>\"\" + \"abc\"</code>&nbsp;，&nbsp;<code>\"a\" + \"bc\"&nbsp;</code>，&nbsp;<code>\"ab\" + \"c\"</code>&nbsp;和&nbsp;<code>\"abc\" + \"\"</code>&nbsp;都是合法分割。</p>\n\n<p>如果 <strong>能构成回文字符串</strong> ，那么请返回&nbsp;<code>true</code>，否则返回<em>&nbsp;</em><code>false</code>&nbsp;。</p>\n\n<p><strong>注意</strong>，&nbsp;<code>x + y</code>&nbsp;表示连接字符串&nbsp;<code>x</code> 和&nbsp;<code>y</code>&nbsp;。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<b>输入：</b>a = \"x\", b = \"y\"\n<b>输出：</b>true\n<b>解释：</b>如果 a 或者 b 是回文串，那么答案一定为 true ，因为你可以如下分割：\na<sub>prefix</sub> = \"\", a<sub>suffix</sub> = \"x\"\nb<sub>prefix</sub> = \"\", b<sub>suffix</sub> = \"y\"\n那么 a<sub>prefix</sub> + b<sub>suffix</sub> = \"\" + \"y\" = \"y\" 是回文串。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>a = \"abdef\", b = \"fecab\"\n<strong>输出：</strong>true\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<b>输入：</b>a = \"ulacfd\", b = \"jizalu\"\n<b>输出：</b>true\n<b>解释：</b>在下标为 3 处分割：\na<sub>prefix</sub> = \"ula\", a<sub>suffix</sub> = \"cfd\"\nb<sub>prefix</sub> = \"jiz\", b<sub>suffix</sub> = \"alu\"\n那么 a<sub>prefix</sub> + b<sub>suffix</sub> = \"ula\" + \"alu\" = \"ulaalu\" 是回文串。</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= a.length, b.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>a.length == b.length</code></li>\n\t<li><code>a</code> 和&nbsp;<code>b</code>&nbsp;都只包含小写英文字母</li>\n</ul>\n",
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