mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-11 02:58:13 +08:00
176 lines
23 KiB
JSON
176 lines
23 KiB
JSON
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"title": "Shortest Completing Word",
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"titleSlug": "shortest-completing-word",
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"content": "<p>Given a string <code>licensePlate</code> and an array of strings <code>words</code>, find the <strong>shortest completing</strong> word in <code>words</code>.</p>\n\n<p>A <strong>completing</strong> word is a word that <strong>contains all the letters</strong> in <code>licensePlate</code>. <strong>Ignore numbers and spaces</strong> in <code>licensePlate</code>, and treat letters as <strong>case insensitive</strong>. If a letter appears more than once in <code>licensePlate</code>, then it must appear in the word the same number of times or more.</p>\n\n<p>For example, if <code>licensePlate</code><code> = "aBc 12c"</code>, then it contains letters <code>'a'</code>, <code>'b'</code> (ignoring case), and <code>'c'</code> twice. Possible <strong>completing</strong> words are <code>"abccdef"</code>, <code>"caaacab"</code>, and <code>"cbca"</code>.</p>\n\n<p>Return <em>the shortest <strong>completing</strong> word in </em><code>words</code><em>.</em> It is guaranteed an answer exists. If there are multiple shortest <strong>completing</strong> words, return the <strong>first</strong> one that occurs in <code>words</code>.</p>\n\n<p> </p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> licensePlate = "1s3 PSt", words = ["step","steps","stripe","stepple"]\n<strong>Output:</strong> "steps"\n<strong>Explanation:</strong> licensePlate contains letters 's', 'p', 's' (ignoring case), and 't'.\n"step" contains 't' and 'p', but only contains 1 's'.\n"steps" contains 't', 'p', and both 's' characters.\n"stripe" is missing an 's'.\n"stepple" is missing an 's'.\nSince "steps" is the only word containing all the letters, that is the answer.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> licensePlate = "1s3 456", words = ["looks","pest","stew","show"]\n<strong>Output:</strong> "pest"\n<strong>Explanation:</strong> licensePlate only contains the letter 's'. All the words contain 's', but among these "pest", "stew", and "show" are shortest. The answer is "pest" because it is the word that appears earliest of the 3.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= licensePlate.length <= 7</code></li>\n\t<li><code>licensePlate</code> contains digits, letters (uppercase or lowercase), or space <code>' '</code>.</li>\n\t<li><code>1 <= words.length <= 1000</code></li>\n\t<li><code>1 <= words[i].length <= 15</code></li>\n\t<li><code>words[i]</code> consists of lower case English letters.</li>\n</ul>\n",
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"translatedTitle": "最短补全词",
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"translatedContent": "<p>给你一个字符串 <code>licensePlate</code> 和一个字符串数组 <code>words</code> ,请你找出 <code>words</code> 中的 <strong>最短补全词</strong> 。</p>\n\n<p><strong>补全词 </strong>是一个包含 <code>licensePlate</code> 中所有字母的单词。<strong>忽略</strong> <code>licensePlate</code> 中的 <strong>数字和空格 </strong>。<strong>不区分大小写</strong>。如果某个字母在 <code>licensePlate</code> 中出现不止一次,那么该字母在补全词中的出现次数应当一致或者更多。</p>\n\n<p>例如:<code>licensePlate</code><code> = \"aBc 12c\"</code>,那么它的补全词应当包含字母 <code>'a'</code>、<code>'b'</code> (忽略大写)和两个 <code>'c'</code> 。可能的 <strong>补全词</strong> 有 <code>\"abccdef\"</code>、<code>\"caaacab\"</code> 以及 <code>\"cbca\"</code> 。</p>\n\n<p>请返回 <code>words</code> 中的 <strong>最短补全词</strong> 。题目数据保证一定存在一个最短补全词。当有多个单词都符合最短补全词的匹配条件时取 <code>words</code> 中 <strong>第一个</strong> 出现的那个。</p>\n\n<p> </p>\n\n<p><strong>示例 1:</strong></p>\n\n<pre>\n<strong>输入:</strong>licensePlate = \"1s3 PSt\", words = [\"step\", \"steps\", \"stripe\", \"stepple\"]\n<strong>输出:</strong>\"steps\"\n<strong>解释:</strong>最短补全词应该包括 \"s\"、\"p\"、\"s\"(忽略大小写) 以及 \"t\"。\n\"step\" 包含 \"t\"、\"p\",但只包含一个 \"s\",所以它不符合条件。\n\"steps\" 包含 \"t\"、\"p\" 和两个 \"s\"。\n\"stripe\" 缺一个 \"s\"。\n\"stepple\" 缺一个 \"s\"。\n因此,\"steps\" 是唯一一个包含所有字母的单词,也是本例的答案。</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<pre>\n<strong>输入:</strong>licensePlate = \"1s3 456\", words = [\"looks\", \"pest\", \"stew\", \"show\"]\n<strong>输出:</strong>\"pest\"\n<strong>解释:</strong>licensePlate 只包含字母 \"s\" 。所有的单词都包含字母 \"s\" ,其中 \"pest\"、\"stew\"、和 \"show\" 三者最短。答案是 \"pest\" ,因为它是三个单词中在 words 里最靠前的那个。\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 <= licensePlate.length <= 7</code></li>\n\t<li><code>licensePlate</code> 由数字、大小写字母或空格 <code>' '</code> 组成</li>\n\t<li><code>1 <= words.length <= 1000</code></li>\n\t<li><code>1 <= words[i].length <= 15</code></li>\n\t<li><code>words[i]</code> 由小写英文字母组成</li>\n</ul>\n",
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"Count only the letters (possibly converted to lowercase) of each word. If a word is shorter and the count of each letter is at least the count of that letter in the licensePlate, it is the best answer we've seen yet."
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1.17<\\/code><\\/p>\\r\\n\\r\\n<p>\\u652f\\u6301 <a href=\\\"https:\\/\\/godoc.org\\/github.com\\/emirpasic\\/gods\\\" target=\\\"_blank\\\">https:\\/\\/godoc.org\\/github.com\\/emirpasic\\/gods<\\/a> \\u7b2c\\u4e09\\u65b9\\u5e93\\u3002<\\/p>\"],\"python3\":[\"Python3\",\"<p>\\u7248\\u672c\\uff1a<code>Python 3.10<\\/code><\\/p>\\r\\n\\r\\n<p>\\u4e3a\\u4e86\\u65b9\\u4fbf\\u8d77\\u89c1\\uff0c\\u5927\\u90e8\\u5206\\u5e38\\u7528\\u5e93\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8 \\u5bfc\\u5165\\uff0c\\u5982<a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/array.html\\\" target=\\\"_blank\\\">array<\\/a>, <a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/bisect.html\\\" target=\\\"_blank\\\">bisect<\\/a>, <a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/collections.html\\\" target=\\\"_blank\\\">collections<\\/a>\\u3002 \\u5982\\u679c\\u60a8\\u9700\\u8981\\u4f7f\\u7528\\u5176\\u4ed6\\u5e93\\u51fd\\u6570\\uff0c\\u8bf7\\u81ea\\u884c\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n<p>\\u5982\\u9700\\u4f7f\\u7528 Map\\/TreeMap \\u6570\\u636e\\u7ed3\\u6784\\uff0c\\u60a8\\u53ef\\u4f7f\\u7528 <a href=\\\"http:\\/\\/www.grantjenks.com\\/docs\\/sortedcontainers\\/\\\" target=\\\"_blank\\\">sortedcontainers<\\/a> \\u5e93\\u3002<\\/p>\"],\"scala\":[\"Scala\",\"<p>\\u7248\\u672c\\uff1a<code>Scala 2.13<\\/code><\\/p>\"],\"kotlin\":[\"Kotlin\",\"<p>\\u7248\\u672c\\uff1a<code>Kotlin 1.3.10<\\/code><\\/p>\"],\"rust\":[\"Rust\",\"<p>\\u7248\\u672c\\uff1a<code>rust 1.58.1<\\/code><\\/p>\\r\\n\\r\\n<p>\\u652f\\u6301 crates.io \\u7684 <a href=\\\"https:\\/\\/crates.io\\/crates\\/rand\\\" target=\\\"_blank\\\">rand<\\/a><\\/p>\"],\"php\":[\"PHP\",\"<p><code>PHP 8.1<\\/code>.<\\/p>\\r\\n\\r\\n<p>With bcmath module.<\\/p>\"],\"typescript\":[\"TypeScript\",\"<p>TypeScript 4.5.4<\\/p>\\r\\n\\r\\n<p>Compile Options: --alwaysStrict --strictBindCallApply --strictFunctionTypes --target ES2020<\\/p>\"],\"racket\":[\"Racket\",\"<p><a href=\\\"https:\\/\\/docs.racket-lang.org\\/guide\\/performance.html#%28tech._c%29\\\" target=\\\"_blank\\\">Racket CS<\\/a> v8.3<\\/p>\\r\\n\\r\\n<p>\\u4f7f\\u7528 #lang racket<\\/p>\\r\\n\\r\\n<p>\\u5df2\\u9884\\u5148 (require data\\/gvector data\\/queue data\\/order data\\/heap). \\u82e5\\u9700\\u4f7f\\u7528\\u5176\\u5b83\\u6570\\u636e\\u7ed3\\u6784\\uff0c\\u53ef\\u81ea\\u884c require\\u3002<\\/p>\"],\"erlang\":[\"Erlang\",\"Erlang\\/OTP 24.2\"],\"elixir\":[\"Elixir\",\"Elixir 1.13.0 with Erlang\\/OTP 24.2\"]}",
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