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leetcode-problemset/leetcode-cn/originData/serialize-and-deserialize-bst.json
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{
"data": {
"question": {
"questionId": "449",
"questionFrontendId": "449",
"categoryTitle": "Algorithms",
"boundTopicId": 1867,
"title": "Serialize and Deserialize BST",
"titleSlug": "serialize-and-deserialize-bst",
"content": "<p>Serialization is converting a data structure or object into a sequence of bits so that it can be stored in a file or memory buffer, or transmitted across a network connection link to be reconstructed later in the same or another computer environment.</p>\n\n<p>Design an algorithm to serialize and deserialize a <b>binary search tree</b>. There is no restriction on how your serialization/deserialization algorithm should work. You need to ensure that a binary search tree can be serialized to a string, and this string can be deserialized to the original tree structure.</p>\n\n<p><b>The encoded string should be as compact as possible.</b></p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n<pre><strong>Input:</strong> root = [2,1,3]\n<strong>Output:</strong> [2,1,3]\n</pre><p><strong>Example 2:</strong></p>\n<pre><strong>Input:</strong> root = []\n<strong>Output:</strong> []\n</pre>\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li>The number of nodes in the tree is in the range <code>[0, 10<sup>4</sup>]</code>.</li>\n\t<li><code>0 &lt;= Node.val &lt;= 10<sup>4</sup></code></li>\n\t<li>The input tree is <strong>guaranteed</strong> to be a binary search tree.</li>\n</ul>\n",
"translatedTitle": "序列化和反序列化二叉搜索树",
"translatedContent": "<p>序列化是将数据结构或对象转换为一系列位的过程,以便它可以存储在文件或内存缓冲区中,或通过网络连接链路传输,以便稍后在同一个或另一个计算机环境中重建。</p>\n\n<p>设计一个算法来序列化和反序列化<strong> 二叉搜索树</strong> 。 对序列化/反序列化算法的工作方式没有限制。 您只需确保二叉搜索树可以序列化为字符串,并且可以将该字符串反序列化为最初的二叉搜索树。</p>\n\n<p><strong>编码的字符串应尽可能紧凑。</strong></p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<pre>\n<strong>输入:</strong>root = [2,1,3]\n<strong>输出:</strong>[2,1,3]\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>root = []\n<strong>输出:</strong>[]\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li>树中节点数范围是 <code>[0, 10<sup>4</sup>]</code></li>\n\t<li><code>0 &lt;= Node.val &lt;= 10<sup>4</sup></code></li>\n\t<li>题目数据 <strong>保证</strong> 输入的树是一棵二叉搜索树。</li>\n</ul>\n",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public var val: Int\n * public var left: TreeNode?\n * public var right: TreeNode?\n * public init(_ val: Int) {\n * self.val = val\n * self.left = nil\n * self.right = nil\n * }\n * }\n */\n\nclass Codec {\n // Encodes a tree to a single string.\n func serialize(_ root: TreeNode?) -> String {\n \n }\n \n // Decodes your encoded data to tree.\n func deserialize(_ data: String) -> TreeNode? {\n \n }\n}\n\n/**\n * Your Codec object will be instantiated and called as such:\n * let ser = Codec()\n * let deser = Codec()\n * let tree: String = ser.serialize(root)\n * let ans = deser.deserialize(tree)\n * return ans\n*/",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode(var `val`: Int) {\n * var left: TreeNode? = null\n * var right: TreeNode? = null\n * }\n */\n\nclass Codec() {\n\t// Encodes a URL to a shortened URL.\n fun serialize(root: TreeNode?): String {\n \n }\n\n // Decodes your encoded data to tree.\n fun deserialize(data: String): TreeNode? {\n \n }\n}\n\n/**\n * Your Codec object will be instantiated and called as such:\n * val ser = Codec()\n * val deser = Codec()\n * val tree: String = ser.serialize(root)\n * val ans = deser.deserialize(tree)\n * return ans\n */",
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"code": "// Definition for a binary tree node.\n// #[derive(Debug, PartialEq, Eq)]\n// pub struct TreeNode {\n// pub val: i32,\n// pub left: Option<Rc<RefCell<TreeNode>>>,\n// pub right: Option<Rc<RefCell<TreeNode>>>,\n// }\n// \n// impl TreeNode {\n// #[inline]\n// pub fn new(val: i32) -> Self {\n// TreeNode {\n// val,\n// left: None,\n// right: None\n// }\n// }\n// }\nuse std::rc::Rc;\nuse std::cell::RefCell;\nstruct Codec {\n\t\n}\n\n/** \n * `&self` means the method takes an immutable reference.\n * If you need a mutable reference, change it to `&mut self` instead.\n */\nimpl Codec {\n fn new() -> Self {\n \n }\n\n fn serialize(&self, root: Option<Rc<RefCell<TreeNode>>>) -> String {\n \n }\n\t\n fn deserialize(&self, data: String) -> Option<Rc<RefCell<TreeNode>>> {\n \n }\n}\n\n/**\n * Your Codec object will be instantiated and called as such:\n * let obj = Codec::new();\n * let data: String = obj.serialize(strs);\n * let ans: Option<Rc<RefCell<TreeNode>>> = obj.deserialize(data);\n */",
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