leetcode-problemset/leetcode-cn/originData/reorder-data-in-log-files.json

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        "question": {
            "questionId": "974",
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            "categoryTitle": "Algorithms",
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            "title": "Reorder Data in Log Files",
            "titleSlug": "reorder-data-in-log-files",
            "content": "<p>You are given an array of <code>logs</code>. Each log is a space-delimited string of words, where the first word is the <strong>identifier</strong>.</p>\n\n<p>There are two types of logs:</p>\n\n<ul>\n\t<li><b>Letter-logs</b>: All words (except the identifier) consist of lowercase English letters.</li>\n\t<li><strong>Digit-logs</strong>: All words (except the identifier) consist of digits.</li>\n</ul>\n\n<p>Reorder these logs so that:</p>\n\n<ol>\n\t<li>The <strong>letter-logs</strong> come before all <strong>digit-logs</strong>.</li>\n\t<li>The <strong>letter-logs</strong> are sorted lexicographically by their contents. If their contents are the same, then sort them lexicographically by their identifiers.</li>\n\t<li>The <strong>digit-logs</strong> maintain their relative ordering.</li>\n</ol>\n\n<p>Return <em>the final order of the logs</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> logs = [&quot;dig1 8 1 5 1&quot;,&quot;let1 art can&quot;,&quot;dig2 3 6&quot;,&quot;let2 own kit dig&quot;,&quot;let3 art zero&quot;]\n<strong>Output:</strong> [&quot;let1 art can&quot;,&quot;let3 art zero&quot;,&quot;let2 own kit dig&quot;,&quot;dig1 8 1 5 1&quot;,&quot;dig2 3 6&quot;]\n<strong>Explanation:</strong>\nThe letter-log contents are all different, so their ordering is &quot;art can&quot;, &quot;art zero&quot;, &quot;own kit dig&quot;.\nThe digit-logs have a relative order of &quot;dig1 8 1 5 1&quot;, &quot;dig2 3 6&quot;.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> logs = [&quot;a1 9 2 3 1&quot;,&quot;g1 act car&quot;,&quot;zo4 4 7&quot;,&quot;ab1 off key dog&quot;,&quot;a8 act zoo&quot;]\n<strong>Output:</strong> [&quot;g1 act car&quot;,&quot;a8 act zoo&quot;,&quot;ab1 off key dog&quot;,&quot;a1 9 2 3 1&quot;,&quot;zo4 4 7&quot;]\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= logs.length &lt;= 100</code></li>\n\t<li><code>3 &lt;= logs[i].length &lt;= 100</code></li>\n\t<li>All the tokens of <code>logs[i]</code> are separated by a <strong>single</strong> space.</li>\n\t<li><code>logs[i]</code> is guaranteed to have an identifier and at least one word after the identifier.</li>\n</ul>\n",
            "translatedTitle": "重新排列日志文件",
            "translatedContent": "<p>给你一个日志数组 <code>logs</code>。每条日志都是以空格分隔的字串，其第一个字为字母与数字混合的<em> </em><strong>标识符 </strong>。</p>\n\n<p>有两种不同类型的日志：</p>\n\n<ul>\n\t<li><strong>字母日志</strong>：除标识符之外，所有字均由小写字母组成</li>\n\t<li><strong>数字日志</strong>：除标识符之外，所有字均由数字组成</li>\n</ul>\n\n<p>请按下述规则将日志重新排序：</p>\n\n<ul>\n\t<li>所有 <strong>字母日志</strong> 都排在 <strong>数字日志</strong> 之前。</li>\n\t<li><strong>字母日志</strong> 在内容不同时，忽略标识符后，按内容字母顺序排序；在内容相同时，按标识符排序。</li>\n\t<li><strong>数字日志</strong> 应该保留原来的相对顺序。</li>\n</ul>\n\n<p>返回日志的最终顺序。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>logs = [\"dig1 8 1 5 1\",\"let1 art can\",\"dig2 3 6\",\"let2 own kit dig\",\"let3 art zero\"]\n<strong>输出：</strong>[\"let1 art can\",\"let3 art zero\",\"let2 own kit dig\",\"dig1 8 1 5 1\",\"dig2 3 6\"]\n<strong>解释：</strong>\n字母日志的内容都不同，所以顺序为 \"art can\", \"art zero\", \"own kit dig\" 。\n数字日志保留原来的相对顺序 \"dig1 8 1 5 1\", \"dig2 3 6\" 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>logs = [\"a1 9 2 3 1\",\"g1 act car\",\"zo4 4 7\",\"ab1 off key dog\",\"a8 act zoo\"]\n<strong>输出：</strong>[\"g1 act car\",\"a8 act zoo\",\"ab1 off key dog\",\"a1 9 2 3 1\",\"zo4 4 7\"]\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 <= logs.length <= 100</code></li>\n\t<li><code>3 <= logs[i].length <= 100</code></li>\n\t<li><code>logs[i]</code> 中，字与字之间都用 <strong>单个</strong> 空格分隔</li>\n\t<li>题目数据保证 <code>logs[i]</code> 都有一个标识符，并且在标识符之后至少存在一个字</li>\n</ul>\n",
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