mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-11 02:58:13 +08:00
188 lines
20 KiB
JSON
188 lines
20 KiB
JSON
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"questionId": "100241",
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"questionFrontendId": "面试题 08.07",
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"categoryTitle": "LCCI",
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"title": "Permutation I LCCI",
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"titleSlug": "permutation-i-lcci",
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"content": "<p>Write a method to compute all permutations of a string of unique characters.</p>\r\n\r\n<p><strong>Example1:</strong></p>\r\n\r\n<pre>\r\n<strong> Input</strong>: S = "qwe"\r\n<strong> Output</strong>: ["qwe", "qew", "wqe", "weq", "ewq", "eqw"]\r\n</pre>\r\n\r\n<p><strong>Example2:</strong></p>\r\n\r\n<pre>\r\n<strong> Input</strong>: S = "ab"\r\n<strong> Output</strong>: ["ab", "ba"]\r\n</pre>\r\n\r\n<p><strong>Note:</strong></p>\r\n\r\n<ol>\r\n\t<li>All charaters are English letters.</li>\r\n\t<li><code>1 <= S.length <= 9</code></li>\r\n</ol>\r\n",
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"translatedTitle": "无重复字符串的排列组合",
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"translatedContent": "<p>无重复字符串的排列组合。编写一种方法,计算某字符串的所有排列组合,字符串每个字符均不相同。</p>\n\n<p> <strong>示例1:</strong></p>\n\n<pre>\n<strong> 输入</strong>:S = \"qwe\"\n<strong> 输出</strong>:[\"qwe\", \"qew\", \"wqe\", \"weq\", \"ewq\", \"eqw\"]\n</pre>\n\n<p> <strong>示例2:</strong></p>\n\n<pre>\n<strong> 输入</strong>:S = \"ab\"\n<strong> 输出</strong>:[\"ab\", \"ba\"]\n</pre>\n\n<p> <strong>提示:</strong></p>\n\n<ol>\n<li>字符都是英文字母。</li>\n<li>字符串长度在[1, 9]之间。</li>\n</ol>\n",
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"difficulty": "Medium",
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"name": "String",
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"slug": "string",
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"translatedName": "字符串",
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"lang": "C++",
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"langSlug": "cpp",
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"code": "class Solution {\npublic:\n vector<string> permutation(string S) {\n\n }\n};",
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"__typename": "CodeSnippetNode"
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},
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"lang": "Java",
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"langSlug": "java",
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"code": "class Solution {\n public String[] permutation(String S) {\n\n }\n}",
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"__typename": "CodeSnippetNode"
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},
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"lang": "Python",
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"langSlug": "python",
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"code": "class Solution(object):\n def permutation(self, S):\n \"\"\"\n :type S: str\n :rtype: List[str]\n \"\"\"",
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"__typename": "CodeSnippetNode"
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},
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"lang": "Python3",
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"langSlug": "python3",
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"code": "class Solution:\n def permutation(self, S: str) -> List[str]:",
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"lang": "C",
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"langSlug": "c",
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"code": "\n\n/**\n * Note: The returned array must be malloced, assume caller calls free().\n */\nchar** permutation(char* S, int* returnSize){\n\n}\n",
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"lang": "C#",
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"langSlug": "csharp",
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"code": "public class Solution {\n public string[] Permutation(string S) {\n\n }\n}",
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"lang": "JavaScript",
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"langSlug": "javascript",
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"code": "/**\n * @param {string} S\n * @return {string[]}\n */\nvar permutation = function(S) {\n\n};",
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"lang": "Ruby",
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"langSlug": "ruby",
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"code": "# @param {String} s\n# @return {String[]}\ndef permutation(s)\n\nend",
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"lang": "Swift",
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"code": "class Solution {\n func permutation(_ S: String) -> [String] {\n\n }\n}",
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"lang": "Go",
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"langSlug": "golang",
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"code": "func permutation(S string) []string {\n\n}",
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"lang": "Scala",
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"langSlug": "scala",
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"code": "object Solution {\n def permutation(S: String): Array[String] = {\n\n }\n}",
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"lang": "Kotlin",
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"langSlug": "kotlin",
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"code": "class Solution {\n fun permutation(S: String): Array<String> {\n\n }\n}",
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"lang": "Rust",
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"langSlug": "rust",
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"code": "impl Solution {\n pub fn permutation(s: String) -> Vec<String> {\n\n }\n}",
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"lang": "PHP",
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"langSlug": "php",
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"code": "class Solution {\n\n /**\n * @param String $S\n * @return String[]\n */\n function permutation($S) {\n\n }\n}",
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"langSlug": "typescript",
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"code": "function permutation(S: string): string[] {\n\n};",
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"lang": "Racket",
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"langSlug": "racket",
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"code": "(define/contract (permutation S)\n (-> string? (listof string?))\n\n )",
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"lang": "Erlang",
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"langSlug": "erlang",
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"code": "-spec permutation(S :: unicode:unicode_binary()) -> [unicode:unicode_binary()].\npermutation(S) ->\n .",
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},
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"lang": "Elixir",
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"langSlug": "elixir",
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"code": "defmodule Solution do\n @spec permutation(s :: String.t) :: [String.t]\n def permutation(s) do\n\n end\nend",
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"hints": [
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"方法1:假设你有abc的所有排列。你怎么用它来得到abcd的所有排列?",
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"方法1:abc的排列组合表示abc的所有组合方式。现在,我们要创建abcd的所有组合方式。选择abcd的特定组合,如bdca。这个bdca字符串也代表abc的一种排列方式:删除d,你会得到bca。那么给定字符串bca,你是否可以创建包含d 的所有“相关”排列组合?",
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"方法1:给定一个字符串,比如bca,可以通过将d 插入到每个可能的位置:dbca、bdca、bcda、bcad,来创建abcd(其中abc顺序一定)的所有排列组合。给定abc的所有排列,你可以创建所有abcd的排列吗?",
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"方法1:你可以通过计算abc的所有排列,然后在每个可能的位置插入d,从而创建abcd的所有排列。",
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"方法2:如果你拥有两个字符所有排列的子串,可以生成三个字符全排列的子串吗?",
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"方法2:生成一个abcd的全排列,需要选择一个初始字符。它可以是a、b、c或d。然后你可以排列其余的字符。如何使用这种方法生成完整字符串的所有排列?",
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"方法 2:要生成abcd的所有排列组合,请选择每个字符(a、b、c、d)作为首字符。排列剩余的字符并追加首字符。如何排列剩余的字符?使用遵循相同逻辑的递归过程。",
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"方法 2:你可以通过让递归函数返回字符串列表来实现该方法,然后在它上面追加首字符。或者,你可以将前缀下推到递归调用中。"
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],
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"solution": null,
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"status": null,
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"sampleTestCase": "\"qwe\"",
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