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"question": {
"questionId": "1793",
"questionFrontendId": "1674",
"categoryTitle": "Algorithms",
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"title": "Minimum Moves to Make Array Complementary",
"titleSlug": "minimum-moves-to-make-array-complementary",
"content": "<p>You are given an integer array <code>nums</code> of <strong>even</strong> length <code>n</code> and an integer <code>limit</code>. In one move, you can replace any integer from <code>nums</code> with another integer between <code>1</code> and <code>limit</code>, inclusive.</p>\n\n<p>The array <code>nums</code> is <strong>complementary</strong> if for all indices <code>i</code> (<strong>0-indexed</strong>), <code>nums[i] + nums[n - 1 - i]</code> equals the same number. For example, the array <code>[1,2,3,4]</code> is complementary because for all indices <code>i</code>, <code>nums[i] + nums[n - 1 - i] = 5</code>.</p>\n\n<p>Return the <em><strong>minimum</strong> number of moves required to make </em><code>nums</code><em> <strong>complementary</strong></em>.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,2,4,3], limit = 4\n<strong>Output:</strong> 1\n<strong>Explanation:</strong> In 1 move, you can change nums to [1,2,<u>2</u>,3] (underlined elements are changed).\nnums[0] + nums[3] = 1 + 3 = 4.\nnums[1] + nums[2] = 2 + 2 = 4.\nnums[2] + nums[1] = 2 + 2 = 4.\nnums[3] + nums[0] = 3 + 1 = 4.\nTherefore, nums[i] + nums[n-1-i] = 4 for every i, so nums is complementary.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,2,2,1], limit = 2\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> In 2 moves, you can change nums to [<u>2</u>,2,2,<u>2</u>]. You cannot change any number to 3 since 3 &gt; limit.\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,2,1,2], limit = 2\n<strong>Output:</strong> 0\n<strong>Explanation:</strong> nums is already complementary.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == nums.length</code></li>\n\t<li><code>2 &lt;= n&nbsp;&lt;=&nbsp;10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= nums[i]&nbsp;&lt;= limit &lt;=&nbsp;10<sup>5</sup></code></li>\n\t<li><code>n</code> is even.</li>\n</ul>\n",
"translatedTitle": "使数组互补的最少操作次数",
"translatedContent": "<p>给你一个长度为<strong> 偶数</strong> <code>n</code> 的整数数组 <code>nums</code> 和一个整数 <code>limit</code> 。每一次操作,你可以将 <code>nums</code> 中的任何整数替换为 <code>1</code> 到 <code>limit</code> 之间的另一个整数。</p>\n\n<p>如果对于所有下标 <code>i</code><strong>下标从 </strong><code>0</code><strong> 开始</strong><code>nums[i] + nums[n - 1 - i]</code> 都等于同一个数,则数组 <code>nums</code> 是 <strong>互补的</strong> 。例如,数组 <code>[1,2,3,4]</code> 是互补的,因为对于所有下标 <code>i</code> <code>nums[i] + nums[n - 1 - i] = 5</code> 。</p>\n\n<p>返回使数组 <strong>互补</strong> 的 <strong>最少</strong> 操作次数。</p>\n\n<p> </p>\n\n<p><strong>示例 1</strong></p>\n\n<pre>\n<strong>输入:</strong>nums = [1,2,4,3], limit = 4\n<strong>输出:</strong>1\n<strong>解释:</strong>经过 1 次操作,你可以将数组 nums 变成 [1,2,<strong>2</strong>,3](加粗元素是变更的数字):\nnums[0] + nums[3] = 1 + 3 = 4.\nnums[1] + nums[2] = 2 + 2 = 4.\nnums[2] + nums[1] = 2 + 2 = 4.\nnums[3] + nums[0] = 3 + 1 = 4.\n对于每个 i nums[i] + nums[n-1-i] = 4 ,所以 nums 是互补的。\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>nums = [1,2,2,1], limit = 2\n<strong>输出:</strong>2\n<strong>解释:</strong>经过 2 次操作,你可以将数组 nums 变成 [<strong>2</strong>,2,2,<strong>2</strong>] 。你不能将任何数字变更为 3 ,因为 3 > limit 。\n</pre>\n\n<p><strong>示例 3</strong></p>\n\n<pre>\n<strong>输入:</strong>nums = [1,2,1,2], limit = 2\n<strong>输出:</strong>0\n<strong>解释:</strong>nums 已经是互补的。\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>n == nums.length</code></li>\n\t<li><code>2 <= n <= 10<sup>5</sup></code></li>\n\t<li><code>1 <= nums[i] <= limit <= 10<sup>5</sup></code></li>\n\t<li><code>n</code> 是偶数。</li>\n</ul>\n",
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