leetcode-problemset/leetcode-cn/originData/minimum-deletions-to-make-array-divisible.json

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            "questionId": "2423",
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            "categoryTitle": "Algorithms",
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            "title": "Minimum Deletions to Make Array Divisible",
            "titleSlug": "minimum-deletions-to-make-array-divisible",
            "content": "<p>You are given two positive integer arrays <code>nums</code> and <code>numsDivide</code>. You can delete any number of elements from <code>nums</code>.</p>\n\n<p>Return <em>the <strong>minimum</strong> number of deletions such that the <strong>smallest</strong> element in </em><code>nums</code><em> <strong>divides</strong> all the elements of </em><code>numsDivide</code>. If this is not possible, return <code>-1</code>.</p>\n\n<p>Note that an integer <code>x</code> divides <code>y</code> if <code>y % x == 0</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [2,3,2,4,3], numsDivide = [9,6,9,3,15]\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> \nThe smallest element in [2,3,2,4,3] is 2, which does not divide all the elements of numsDivide.\nWe use 2 deletions to delete the elements in nums that are equal to 2 which makes nums = [3,4,3].\nThe smallest element in [3,4,3] is 3, which divides all the elements of numsDivide.\nIt can be shown that 2 is the minimum number of deletions needed.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [4,3,6], numsDivide = [8,2,6,10]\n<strong>Output:</strong> -1\n<strong>Explanation:</strong> \nWe want the smallest element in nums to divide all the elements of numsDivide.\nThere is no way to delete elements from nums to allow this.</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length, numsDivide.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= nums[i], numsDivide[i] &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
            "translatedTitle": "使数组可以被整除的最少删除次数",
            "translatedContent": "<p>给你两个正整数数组&nbsp;<code>nums</code> 和&nbsp;<code>numsDivide</code>&nbsp;。你可以从&nbsp;<code>nums</code>&nbsp;中删除任意数目的元素。</p>\n\n<p>请你返回使 <code>nums</code>&nbsp;中 <strong>最小</strong>&nbsp;元素可以整除 <code>numsDivide</code>&nbsp;中所有元素的 <strong>最少</strong>&nbsp;删除次数。如果无法得到这样的元素，返回 <code>-1</code>&nbsp;。</p>\n\n<p>如果&nbsp;<code>y % x == 0</code>&nbsp;，那么我们说整数&nbsp;<code>x</code>&nbsp;整除&nbsp;<code>y</code>&nbsp;。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><b>输入：</b>nums = [2,3,2,4,3], numsDivide = [9,6,9,3,15]\n<b>输出：</b>2\n<b>解释：</b>\n[2,3,2,4,3] 中最小元素是 2 ，它无法整除 numsDivide 中所有元素。\n我们从 nums 中删除 2 个大小为 2 的元素，得到 nums = [3,4,3] 。\n[3,4,3] 中最小元素为 3 ，它可以整除 numsDivide 中所有元素。\n可以证明 2 是最少删除次数。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><b>输入：</b>nums = [4,3,6], numsDivide = [8,2,6,10]\n<b>输出：</b>-1\n<b>解释：</b>\n我们想 nums 中的最小元素可以整除 numsDivide 中的所有元素。\n没有任何办法可以达到这一目的。</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length, numsDivide.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= nums[i], numsDivide[i] &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
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                "How can we find an integer x that divides all the elements of numsDivide?",
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